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2 years ago

Suppose that cos = 12/13 what is sin what is cos 2

1 answer:

riadik2000 [5.3K]2 years ago

8 0

First, some housekeeping:

cos = 12/13 is incomplete; "cos" must have an argument (input).

cos x = 12/13 is fine; here "cos" has the argument (input) x.

Given that cos x = 12/13, find sin x. To do this, we'll need to find the length of the opposite side, given that the hypo length is 13 and the adj. side length is 12.

12^2 + opp^2 = 13^2, or opp^2 = 169-144 = 25.

Then the opp side could be either 5 or -5. Let's assume that it's +5, and that angle x is in the first quadrant.

Then sin x = opp / hyp = 5/13 (answer)

cos 2 is an entirely different kind of problem. Here you are told what the argument (input) to the cosine function is (it is 2, which here means 2 radians).

Using a calculator: cos 2 = -0.416. Note that the angle 2 rad is in QII, which is why the "adjacent side" is negative and also why the cos of 2 is negative.

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5 movie tickets cost $55. At this rate, what is the cost per ticket?

Mariana [72]

Answer:

Step-by-step explanation:

55/5 equals 11

4 0

2 years ago

Read 2 more answers

Factor 6(2p q)^2 -5(2p q) - 25

kherson [118]

Treat the 2p+q as x

6x2-5x-25
trial and error
(2x-5)(3x+5)
replace x with (2p+q)
(2(2p+q)-5)(3(2p+q)+5)
(4p+2q-5)(6p+3q+5)

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3 years ago

Charlie does a weekly exercise program consisting of cardiovascular work and weight training. Each week, he exercises for at lea

german

Answer:

$(x_1,y_1) = (0,9)$

$(x_2,y_2) = (6,3)$

$(x_3,y_3) = (6,12)$

Step-by-step explanation:

Given

x = hours spent on cardiovascular work

y = hours spent on weight training

From the first statement,

Each week: he spends at least 9 hours

This is represented as:

$Total \ge 9$

$x + y \ge 9$

From the second statement,

Each week: he spends a max of 12 hours on weights

This is represented as:

$Weight \le 12$

$y \le 12$

From the third statement,

Each week: he spends a max of 6 hours on cardio works

This is represented as:

$Cardio \le 6$

$x \le 6$

So, the inequalities are:

$x + y \ge 9$

$y \le 12$

$x \le 6$

See attachment for the graph where the solution are also highlighted

From the attachment, the solutions are:

$(x_1,y_1) = (0,9)$

$(x_2,y_2) = (6,3)$

$(x_3,y_3) = (6,12)$

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2 years ago

What is the GCF of 4 and 5

Alexxx [7]

8 and 25 thats the answer

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2 years ago

Read 2 more answers

Question 3 (1 point) Co-60 has a half life of 5.3 years. If a pellet that has been in storage for 26.5 years contains 14.5g of C

Zarrin [17]

Answer:

464 grams.

Step-by-step explanation:

Amount of substance:

The amount of substance after t years is given by an equation in the following format:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Co-60 has a half life of 5.3 years.

This means that:

$A(5.3) = 0.5A(0)$

We use this to find r. So

$A(t) = A(0)(1-r)^t$

$0.5A(0) = A(0)(1-r)^{5.3}$

$(1-r)^{5.3} = 0.5$

$\sqrt[5.3]{(1-r)^{5.3}} = \sqrt[5.3]{0.5}$

$1 - r = 0.5^{\frac{1}{5.3}}$

$1 - r = 0.8774$

$A(t) = A(0)(0.8774)^{t}$

If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?

We have that $A(26.5) = 14.5$ , and use this to find A(0). So

$A(t) = A(0)(0.8774)^{t}$

$14.5 = A(0)(0.8774)^{26.5}$

$A(0) = \frac{14.5}{(0.8774)^{26.5}}$

[tex]A(0) = 464[tex]

464 grams.

3 0

3 years ago