Answer: The 2nd and 3rd one are correct
Step-by-step explanation:
After reflecting it, the square itself would not change, only the position of the square. Therefore, the same line segments from the beginning which were given would be parallel.
It’s b. :) hope this helps you
The given equality hold true when x = 2.
Put x = 2 in inequality.
2(2) + 3 = 4+3 = 7 = R.H.S.
For x = 4 and 6, L.H.S(2x+3) is greater than 7.
Hence for x = 2, 4 and 6, the above inequality holds true.
Hope this helps!
Answer: 115%
Step-by-step explanation: ur welcome
Answer:
alr 5x+11 and 2x-3
5x+11=16x
2x-3=-1x
Step-by-step explanation:
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