Answer:
length is 20 and the width is 5
Step-by-step explanation:
so Area is 100
Area = width * length
legth = 4 * width
This means:
Area = width * 4 width => Area = 5 * width
We know that area is 100 so:
100 = 5 * width
that means width = 20, but wait didn't I say that the length is 20? Yes, remember we said length = 4 * width at the beginning, so <u>length = 20</u>.
Now we can easily calculate width as width is 4 times smaller than length, so:
<u>width = 20/4 => 5</u>
We can also test if this is correct by simply using the formula to calculate rectangle. So 5 * 20 = 100, correct!
The equation of the piecewise function is 
<h3>The piecewise function</h3>
On the graph, we have:
- y = 3 for all x values not more than -1
- y = -1 for all values greater than 2
Hence, the piecewise function is:
<h3>The domain of the function</h3>
This is the set of input values
In (a), we have:
x ≤ -1 and x > 2
Hence, the domain is (∞, 3] u (2, ∞)
<h3>The range of the function</h3>
This is the set of output values
In (a), we have:
f(x) = 3 and f(x) -1
Hence, the range is [3] u (-1)
Read more about piecewise function at:
brainly.com/question/18859540
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Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
7, 5, 1, 6, 2 Mean Absolute Deviation = 2.16
3, 6, 3, 2, 1 Mean Absolute Deviation = 1.2
