Answer:
Mass of carbon dioxide = 7.48 g
Explanation:
Given data:
Mass of lithium carbonate = 12.5 g
Mass of carbon dioxide produced = ?
Solution:
Chemical equation:
Li₂CO₃ → Li₂O + CO₂
Number of moles of Li₂CO₃:
Number of moles = mass/ molar mass
Number of moles = 12.5 g /73.89 g/mol
Number of moles = 0.17 mol
Now we will compare the moles of Li₂CO₃ with CO₂.
Li₂CO₃ : CO₂
1 : 1
0.17 : 0.17
Mass of carbon dioxide:
Mass of carbon dioxide = number of moles × molar mass
Mass of carbon dioxide = 0.17 mol × 44 g/mol
Mass of carbon dioxide = 7.48 g
Answer:
3.23 atm
Explanation:
Use the equation P₁V₁=P₂V₂. P₁ and V₁ are initial pressure and volume. P₂ and V₂ are final pressure and volume. Solve for P₂.
(1.88 L)(3.81 atm) = (2.22 L)(P₂)
7.1628 L*atm = (2.22 L)(P₂)
P₂ = 3.226 atm
Becouse melting point and cooling point are two opposite things one is 100degrees nd other 0degrees
Answer:
p = 1.5 atm
Explanation:
pV = nRT
p = nRT/V = [1.8 mol×(0.082 atm L/mol K)×247.8 K]/24.5 L
p = 1.5 atm
