What is the pressure, in atm, of 24.5 L of ideal gas at 247.8 K if there are 1.8 moles present?
1 answer:
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Answer:
1.99 x 10²³ formula units
Explanation:
Given parameters:
Mass of AgF = 42.15g
Unknown:
The amount of formula units
Solution:
To solve this problem, we set out by find the number of moles in this compound from the given mass.
Number of moles =
molar mass of AgF = 107.9 + 19 = 126.9g/mol
Number of moles = = 0.33 moles
1 mole of a substance = 6.02 x 10²³ formula units
0.33 moles of AgF = 0.33 x 6.02 x 10²³ = 1.99 x 10²³ formula units
Answer:
1. Yes
2.The solubility of X is 34.55g/L
Explanation:
Solubility of solute refers to how readily a solute will dissolve in a solvent at a particular temperature. Its the amount of moles or grams required to saturate 1dm or 1 Litre of water.
From the problem, when the liquid was drained off and amount of X which didn't dissolve was measured, it weighed 0.008kg, this means out of 0.027kg, 0.027-0.008 actually dissolved
= 0.019kg*1000 = 19g.
if 19g is required to saturate 550mL at 30°C,
then will saturate 1L
= 34.545g will saturate 1Litre
The solubility thus is 34.55g/L
Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve for the molarity of the KOH solution by knowing this base react in a 1:1 mole ratio with nitric acid, HNO3; thus, we can write the following equation, as their moles are the same at the endpoint:
Which in terms of molarities and volumes is:
Thus, we solve for the molarity of the base (KOH) to obtain:
Regards!