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Monica [59]
3 years ago
8

Give me lil reasoning so I know your not lying for points

Chemistry
1 answer:
ycow [4]3 years ago
4 0

Answer:

0.87 ATM

Explanation:

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In a polar covalent bond, the distribution of common electrons are not shared evenly due to a greater positive charge from one atom's nucleus.Oct 30, 2016

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After balancing the following reaction under acidic conditions, how many mole equivalents of water are required and on which sid
nordsb [41]

Answer:

d. 8 moles of H2O on the product side

Explanation:

Hello,

In this case, we need to balance the given redox reaction in acidic media as shown below:

MnO_4^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O\\\\2Cl^{1-}\rightarrow Cl_2^0+2e^-\\\\2*[(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O]\\\\5*[2Cl^{1-}\rightarrow Cl_2^0+2e^-]\\\\\\\\2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10e^- \rightarrow 2Mn^{2+}+8H_2O\\\\10Cl^{1-}\rightarrow 5Cl_2^0+10e^-\\

Then, we add the half reactions:

2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10Cl^{1-} \rightarrow 2Mn^{2+}+8H_2O+5Cl_2^0

Thereby, we can see d. 8 moles of H2O on the product side.

Best regards.

4 0
2 years ago
A non-metallic atom(at.no. 9) forms a molecule of the same,containing a single covalent bond. give reason
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They are so may forms
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2 years ago
What is the best way to maintain control of the subsection when cutting with a vertical or diagonal cutting line
barxatty [35]

Palm to palm is referred to as the best way to maintain control of the subsection when cutting with a vertical or diagonal cutting line thereby preventing the risk of injuries or inaccuracy.

<h3>What is Palm to palm technique?</h3>

This method is used during cutting or styling and involves the two palms of the hands in a position such that they are facing each other or opposite to one another and helps to reduce the different types of strain in the affected part of the body.

This method isn't a compulsory one to be done but is best suited for an individual who wants to maintain control of the subsection when cutting with a vertical or diagonal cutting line.

This is therefore the main reason why palm-to palm technique was chosen as the most appropriate choice.

Read more about Palm to palm technique here brainly.com/question/5029605

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3 0
1 year ago
In a laboratory experiment, students synthesized a new compound and found that when 7.229 grams of the compound were dissolved i
STALIN [3.7K]

The question is incomplete, here is the complete question:

The common laboratory solvent chloroform is often used to purify substances dissolved in it. The vapor pressure of chloroform, CHCl₃, is 173.11 mm Hg at 25°C.

In a laboratory experiment, students synthesized a new compound and found that when 7.229 grams of the compound were dissolved in 207.8 grams of chloroform, the vapor pressure of the solution was 170.51 mm Hg. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight of this compound?

<u>Answer:</u> The molecular mass of the compound is 481.9 g/mol

<u>Explanation:</u>

The equation used to calculate relative lowering of vapor pressure follows:

\frac{p^o-p_s}{p^o}=i\times \chi_{solute}

where,

\frac{p^o-p_s}{p^o} = relative lowering in vapor pressure

i = Van't Hoff factor = 1 (for non electrolytes)

\chi_{solute} = mole fraction of solute = ?

p^o = vapor pressure of pure chloroform = 173.11 mmHg

p_s = vapor pressure of solution = 170.51 mmHg

Putting values in above equation, we get:

\frac{173.11-170.51}{173.11}=1\times \chi_A\\\\\chi_A=0.0150

This means that 0.0150 moles of compound is present in the solution

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of compound = 0.0150 moles

Given mass of compound = 7.229 g

Putting values in above equation, we get:

0.0150mol=\frac{7.229g}{\text{Molar mass of compound}}\\\\\text{Molar mass of compound}=\frac{7.229g}{0.0150mol}=481.9g/mol

Hence, the molecular mass of the compound is 481.9 g/mol

5 0
2 years ago
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