Its all the way round true 99.9% sure because they launch baometers up in the air and it reflects off of the satalght
Answer:
120g
Explanation:
Step 1:
We'll begin by writing the balanced equation for the reaction.
Sn + 2HF —> SnF2 + H2
Step 2:
Determination of the number of mole HF needed to react with 3 moles of Sn.
From the balanced equation above,
1 mole of Sn and reacted with 2 moles of HF.
Therefore, 3 moles Sn will react with = 3 x 2 = 6 moles of HF.
Step 3:
Conversion of 6 moles of HF to grams.
Number of mole HF = 6 moles
Molar Mass of HF = 1 + 19 = 20g/mol
Mass of HF =..?
Mass = number of mole x molar Mass
Mass of HF = 6 x 20
Mass of HF = 120g
Therefore, 120g of HF is needed to react with 3 moles of Sn.
Answer:
5.78 × 10¹⁴ Hz
Explanation:
Step 1: Given and required data
- Wavelength of this light (λ): 519. nm
- Frecquency of this light (ν): ?
- Speed of light (c): 3.00 × 10⁸ m/s
Step 2: Convert "λ" to meters
We will use the conversion factor 1 m = 10⁹ nm.
519. nm × 1 m/10⁹ nm = 5.19 × 10⁻⁷ m
Step 3: Calculate the frecquency of this light
We will use the following expression.
c = λ × ν
ν = c/λ
ν = (3.00 × 10⁸ m/s)/5.19 × 10⁻⁷ m
ν = 5.78 × 10¹⁴ s⁻¹ = 5.78 × 10¹⁴ Hz
Answer:
Percentage = 40%
Explanation:
Given data:
Mass of SO₄ = 2.00 g
Mass of BaSO₄ = 5.00 g
Percentage of SO₄ = ?
Solution:
Percentage of any substance can be calculated by following formula.
Percentage = given amount / total amount × 100
Now we will calculate the percentage of SO₄.
Percentage = 2.00 g / 5.00 × 100
Percentage = 0.4 × 100
Percentage = 40%