In a sample of H2SO4 that contain 200 S atom the number of hydrogen atoms would be 400 atoms
explanation
there are two moles of H2 in H2SO4 therefore by use of ratio between S:H2 which is 1:2 atoms therefore the atoms of hydrogen = 2 x200 = 400 atoms
Answer:
<u>a</u><u>.</u><u> </u><u>True</u><u>.</u>
Explanation:
Only primary and secondary alcohols can oxidise to give an aldehyde. But a weak oxidizing agent must be used to prevent formation of a carboxylic acid or ketone.
weak oxidizing agents: Chromyl chloride, silver/oxygen/500°C
take an example of <u>e</u><u>t</u><u>h</u><u>a</u><u>n</u><u>o</u><u>l</u><u>:</u>
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<u>B</u><u>y</u><u> </u><u>o</u><u>z</u><u>o</u><u>n</u><u>o</u><u>l</u><u>y</u><u>s</u><u>i</u><u>s</u><u>:</u>
Here, reactants are Ozone gas, Carbon tetrachloride at a temperature (<20°C), ethanoic acid, zinc and water.
take an example of propanol:
if it undergoes ozonolysis, it gives ethanal and methanal.
Clearly H2 is in gaseous state as could be seen from (g) written with it which tells state of the product
Answer:
3.87 x 10^24
Explanation:
Simply multiply the moles by avogadros number
6.42 moles of H2O x 6.022 x 10^23 molecules/1 mole of H2O = 3.87 x 10^24 molecules of H2O
Answer is: the molarity of a solution of HF is 0.73 M.
n(HF) = 4.400 mol; amount of hydrofluoric acid.
V(HF) = 6.00 l; volume of hydrofluoric acid.
c(HF) = n(HF) ÷ V(HF).
c(HF) = 4.400 mol ÷ 6.00 l.
c(HF) = 0.733 mol/l; molarity of a solution (hydrofluoric acid).