4 years ago

When C-14 decays, it forms nitrogen, a(n) _ particle, and a(n) _.

Chemistry

2 answers:

Karo-lina-s [1.5K]4 years ago

5 0

Alpha;Neutrino
Ur Welcomes!Lol

denis-greek [22]4 years ago

3 0

Answer:

Alpha;neutrino

Explanation:

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Explanation:

Given and known facts

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Now, we know that

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$\frac{ -7.82 }{0.187}\\= -41.8$

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4 years ago

When C-14 decays, it forms nitrogen, a(n) _____ particle, and a(n) _____.

When C-14 decays, it forms nitrogen, a(n) _ particle, and a(n) _.