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Ulleksa [173]
3 years ago
10

Is a particle with a positive charge.:)

Chemistry
1 answer:
tatyana61 [14]3 years ago
8 0
Proton is the answer
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A green rat snake that lives in the grass and a brown rat snake that lives in the desert is a form of what ?
liberstina [14]

A green rat snake that lives in the grass and a brown rat snake that lives in the desert is a form of geographically separated species.

Explanation:

The habitats of the green rat snake  and brown rat snake shows that they are geographically separated species.

The two rat snakes are different species because of their distinct habitat and morphology.

When two species get separated by habitat their breeding method changes either by morphology or breeding pattern.

Such species do not produce viable offspring.

Thus a green rat snake and a brown rat snake have very different habitats they are now two different species.

Such species are said to be reproductively isolated species. Two species having genetic divergence undergo natural selection to adapt to the environment.

6 0
3 years ago
The molarity of an aqueous sodium phosphate solution is 0.650 M. What is the molality of sodium ions present in this solution? T
netineya [11]

Answer:

molality of sodium ions is 1.473 m

Explanation:

Molarity is moles of solute per litre of solution

Molality is moles of solute per kg of solvent.

The volume of solution = 1 L

The mass of solution = volume X density = 1000mL X 1.43 = 1430 grams

The mass of solute = moles X molar mass of sodium phosphate = 0.65X164

mass of solute = 106.6 grams

the mass of solvent = 1430 - 106.6 = 1323.4 grams = 1.3234 Kg

the molality = \frac{moles of solute}{mass of solvent in kg}=\frac{0.65}{1.323}= 0.491m

Thus molality of sodium phosphate is 0.491 m

Each sodium phosphate of molecule will give three sodium ions.

Thus molality of sodium ions = 3 X 0.491 = 1.473 m

7 0
3 years ago
Some type of path is necessary to join both half-cells in order for electron flow to occur.
klemol [59]

The given statement, some type of path is necessary to join both half-cells in order for electron flow to occur, is true.

Explanation:

Flow of electrons is possible with the help of a conducting medium like metal wire.

A laboratory device which helps in completion of oxidation and reduction-half reactions of a galvanic or voltaic cell is known as salt bridge. Basically, this salt bridge helps in the flow of electrons from anode to cathode and vice-versa.

If salt bridge is not present in an electrochemical cell, the electron neutrality will not be maintained and hence, flow of electrons will not take place.

Thus, we can conclude that the statement some type of path is necessary to join both half-cells in order for electron flow to occur, is true.

4 0
3 years ago
Read the following chemical equation: Ti + 2Cl2 → TiCl4 Which statement best identifies and describes the reducing agent in the
goldenfox [79]

Answer: Ti is the reducing agent because it changes from 0 to +4 oxidation state.

Explanation:

  • Firstly, we need to identify the reducing agent and the oxidizing agent.
  • The reducing agent: is the agent that has been oxidized via losing electrons.
  • The oxidizing agent: is the agent that has been reduced via gaining electrons.
  • Here, Ti losses 4 electrons and its oxidation state is changed from 0 to +4 and Cl₂  gains one electron  and its oxidation state is changed from 0 to -1.
  • So, Ti is the reducing agent because its oxidation state changes from  0 to +4.
  • Cl₂ is the oxidizing agent because its oxidation state changes from 0 to -1.
  • Thus, The right answer is Ti is the reducing agent because it changes from 0 to +4 oxidation state.
4 0
3 years ago
How much ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.
Tanya [424]

Answer:

An insulated beaker with negligible mass contains liquid water with a mass of 0.205kg and a temperature of 79.9 °C How much ice at a temperature of −17.5 °C must be dropped into the water so that the final temperature of the system will be 31.0 °C? Take the specific heat for liquid water to be 4190J/Kg.K, the specific heat for ice to be 2100J/Kg.K, and the heat of fusion for water to be 334000J/kg.

The answer to the above question is

Therefore 0.1133 kg  ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.0 °C

Explanation:

To solve this we proceed by finding the heat reaquired to raise the temperature of the water to 31.0 C from 79.9 C then we use tht to calculate for the mass of ice as follows

ΔH = m×c×ΔT

= 0.205×4190×(79.9 -31.0) = 42002.655 J

Therefore fore the ice, we have

Total heat = mi×L + mi×ci×ΔTi = mi×334000 + mi × 2100 × (0 -−17.5) = 42002.655 J

370750×mi = 42002.655 J

or mi = 0.1133 kg

Therefore 0.1133 kg  ice at a temperature of -17.5 ∘C must be dropped into the water so that the final temperature of the system will be 31.0 °C

5 0
3 years ago
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