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Gennadij [26K]
3 years ago
8

Which weather condition can be described as clouds at ground level?

Chemistry
2 answers:
IRINA_888 [86]3 years ago
8 0

Answer:

fog

Explanation:

fog

PtichkaEL [24]3 years ago
6 0
A cloud that forms on the ground is called fog. Some clouds you see in the sky might be from airplanes. These are called contrails. High level cirrus clouds may travel at speeds up to 100 mph.
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A(n) _____, used as part of the stationary phase, has an affinity for the solvent and the chemical components of the mixture. ad
tester [92]

The answer is Adsorbent

The adsorbent has a high affinity for solvent and the chemical components of the mixture.

Chromatography is a method of separation in which the mixture of substances is introduced into a mobile phase (solvent). The separation occurs as the solvent interacts with an adsorbent(stationary phase).

The extent of separation of the components of the mixture depends on the extent of interaction between the mobile and the stationary phase . This interaction also determines the retention factor (Rf) of the separation.

For a definition of chromatography, see

brainly.com/question/19334271

4 0
3 years ago
Will mark brainliest
nexus9112 [7]

Answer:

universal law of gravitation

Explanation:

6 0
3 years ago
How much work is done if the sled moves 10 m horizontally
Sauron [17]

probably none becuase it going staright unless its going down a hill

7 0
3 years ago
When the pressure that a gas exerts
Ronch [10]

Answer:

The pressure changes from 2.13 atm to 1.80 atm.

Explanation:

Given data:

Initial pressure = ?

Final pressure = 1.80 atm

Initial temperature = 86.0°C (86.0 + 273 = 359 K)

Final temperature = 30.0°C (30+273 =303 K)

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

P₁ = P₂T₁ /T₂

P₁ = 1.80 atm × 359 K / 303 K

P₁ = 646.2 atm. K /303 K

P₁ = 2.13 atm

The pressure changes from 2.13 atm to 1.80 atm.

5 0
3 years ago
Read 2 more answers
A mixture of three gases has a total pressure at 298 K of 1560 mm Hg. the mixture is analyzed and is found to contain 1.50 mol N
Agata [3.3K]

Answer:

the partial pressure of Xe is 452.4 mmHg

Explanation:

Dalton's law of partial pressures says that in a mixture of non-reacting gases, the total pressure exerted is equal to the sum of the partial pressures of the individual gases.

The partial pressures can be calculated with the molar fraction of the gas, in this case, Xe.

Molar fraction of Xe is calculated as follows:

x_{Xe}=\frac{n_{Xe} }{n_{t} }

x_{Xe}=1.75/5.9\\x_{Xe}=0.29

Then, 0.29 is the molar fraction of Xe in the mixture of gases given.

To know the parcial pressure of Xe, we have to multiply the molar fraction by the total pressure:

Partial Pressure of Xe=1560mmHg*0.29

Partial Pressure of Xe=452.4mmHg

7 0
3 years ago
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