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snow_lady [41]
3 years ago
12

Please helppp !!

Chemistry
1 answer:
Alex787 [66]3 years ago
7 0
D ................................
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Balance CH2O + H2 > CH3OH
Tju [1.3M]

Answer:

I believe it is balanced

Explanation:

8 0
3 years ago
An unknown metal forms a soluble compound, M(NO3)2, which then undergoes electrolysis with an applied current of 2.50 amperes. I
frozen [14]

Answer:

The metal is the cathode

The metal is palladium

At the other cathode, the reaction going on is

M(s) ------> M2^+(aq) + 2e

Chlorine can spontaneously react with Pd converting it to Pd^2+

The molar mass of the metal is 106.4 g of M

Explanation:

Given the formula of the compound, M^2+ ion is involved. The equation of the reaction is;

M^2+(aq) + 2e -------------> M(s)

The number of moles of electrons transferred = 2 moles

1 mole of electron = 96500C

And Q= It

Where I= current

t= time taken in seconds

Now;

x g of the metal (its molar mass) is deposited by 2×96500 C

1.87 g of the metal is deposited by (2.50× 22.6×60) C

x = 1.87 × 2×96500/ 2.50 × 22.6 × 60

x= 360910/3390

x= 106.4 g of M

The metal is the cathode

The metal is palladium

At the other cathode, the reaction going on is

M(s) ------> M2^+(aq) + 2e

Chlorine can spontaneously react with Pd converting it to Pd^2+

7 0
3 years ago
How many moles, kmols in: 100 g of CO2, 1 litre of ethyl alcohol of density 0.789 g/cm3 and a) 1.5m3 of O2 at 25°C and 1 atm. b)
Nutka1998 [239]

Explanation:

1) Mass of carbon dioxide = 100 g

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide =\frac{100 g}{44 g/mol}=2.273 moles

1 mol = 0.001 kmol

2.273 moles= 2.273 × 0.001 kmol = 2.273\times 10^{-3} kmol

2) 1 liter of ethyl alcohol of density 0.789 g/cm^3

Volume of ethyl alcohol ,V= 1 L = 1000 mL

Density of ethyl alcohol =d = 0.789 g/cm^3

1 cm^3=1 mL

Mass of ethyl alcohol = m

m=d\times V=0.789 g/cm^3\times 1000 mL=789 g

Molar mass of  ethyl alcohol = 46 g/mol

Moles of ethyl alcohol = \frac{789 g}{46 g/mol}=17.152 mol

17.152 mol=17.152\times 0.001 kmol=1.7152\times 10^{-4} kmol

3) Volume of oxygen gas,V =1.5 m^3=1500 L

1 m^3= 1000 L

Temperature of the gas = T= 25°C = 298.15 K

Pressure of the gas ,P= 1 atm

Moles of oxygen gas = n

PV=nRT

n=\frac{RT}{PV}=\frac{0.0821 atm L/mol K\times 298.15 K}{1 atm\times 1500 L}=0.01632 mol

0.01632 mol = 0.01632 × 0.001 kmol=1.632\times 10^{-5} kmol

4) Volume water in mixture = 1 L

Density of water =  1000 kg/m^3=\frac{1,000,000 g}{1000 L}=1000 g/L

Mass of water = 1000 g/L\times 1 L = 1000 g

Volume of alcohol = 2.5 L

Density of alcohol =  789 kg/m^3=\frac{789000 g}{1000 L}=789 g/L

Mass of alcohol = 789 g/L\times 2.5 L = 1972.5 g

Mass of mixture = 1000 g + 1972.5 g = 2972.5 g

Mass percentage of water :

\frac{1000 g}{2972.5 g}\times 100=33.64\%

Mass percentage of alcohol :

\frac{1972.5 g}{2972.5 g}\times 100=66.36\%

Moles of water :

n_1=\frac{1000 g}{18 g/mol}=55.55 mol

Moles of alcohol =

n_2=\frac{1972.5 g}{46 g/mol}=42.88 mol

Mole fraction of water :

\chi_1=\frac{n_1}{n_1+n_2}=\frac{55.55 mol}{55.55 mol+42.88 mol}=0.5644

Mole fraction of alcohol :

\chi_2=\frac{n_2}{n_1+n_2}=\frac{42.88 mol}{55.55 mol+42.88 mol}=0.4356

3 0
3 years ago
Trick to change word equation to chemical equation​
Elden [556K]

Answer:

actually word equation has the names and we need to write molecular formula in chemical eqn. so I don't think there is sort of trick.You just need to memorise the molecular formula of chemicals.

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Definition plz someone plz plz plz
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Force: any interaction that, when unopposed, will change the motion of an object.

Mass: the quantity of matter in a body regardless of its volume or of any forces acting on it

Acceleration: rate of change of velocity of an object with respect to time
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