Please helppp !!

Balance CH2O + H2 > CH3OH

Tju [1.3M]

Answer:

I believe it is balanced

Explanation:

8 0

3 years ago

An unknown metal forms a soluble compound, M(NO3)2, which then undergoes electrolysis with an applied current of 2.50 amperes. I

frozen [14]

Answer:

The metal is the cathode

The metal is palladium

At the other cathode, the reaction going on is

M(s) ------> M2^+(aq) + 2e

Chlorine can spontaneously react with Pd converting it to Pd^2+

The molar mass of the metal is 106.4 g of M

Explanation:

Given the formula of the compound, M^2+ ion is involved. The equation of the reaction is;

M^2+(aq) + 2e -------------> M(s)

The number of moles of electrons transferred = 2 moles

1 mole of electron = 96500C

And Q= It

Where I= current

t= time taken in seconds

Now;

x g of the metal (its molar mass) is deposited by 2×96500 C

1.87 g of the metal is deposited by (2.50× 22.6×60) C

x = 1.87 × 2×96500/ 2.50 × 22.6 × 60

x= 360910/3390

x= 106.4 g of M

The metal is the cathode

The metal is palladium

At the other cathode, the reaction going on is

M(s) ------> M2^+(aq) + 2e

Chlorine can spontaneously react with Pd converting it to Pd^2+

7 0

3 years ago

How many moles, kmols in: 100 g of CO2, 1 litre of ethyl alcohol of density 0.789 g/cm3 and a) 1.5m3 of O2 at 25°C and 1 atm. b)

Nutka1998 [239]

Explanation:

1) Mass of carbon dioxide = 100 g

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = $\frac{100 g}{44 g/mol}=2.273 moles$

1 mol = 0.001 kmol

2.273 moles= 2.273 × 0.001 kmol = $2.273\times 10^{-3} kmol$

2) 1 liter of ethyl alcohol of density $0.789 g/cm^3$

Volume of ethyl alcohol ,V= 1 L = 1000 mL

Density of ethyl alcohol =d = $0.789 g/cm^3$

$1 cm^3=1 mL$

Mass of ethyl alcohol = m

$m=d\times V=0.789 g/cm^3\times 1000 mL=789 g$

Molar mass of ethyl alcohol = 46 g/mol

Moles of ethyl alcohol = $\frac{789 g}{46 g/mol}=17.152 mol$

$17.152 mol=17.152\times 0.001 kmol=1.7152\times 10^{-4} kmol$

3) Volume of oxygen gas,V = $1.5 m^3=1500 L$

$1 m^3= 1000 L$

Temperature of the gas = T= 25°C = 298.15 K

Pressure of the gas ,P= 1 atm

Moles of oxygen gas = n

$PV=nRT$

$n=\frac{RT}{PV}=\frac{0.0821 atm L/mol K\times 298.15 K}{1 atm\times 1500 L}=0.01632 mol$

0.01632 mol = 0.01632 × 0.001 kmol= $1.632\times 10^{-5} kmol$

4) Volume water in mixture = 1 L

Density of water = $1000 kg/m^3=\frac{1,000,000 g}{1000 L}=1000 g/L$

Mass of water = $1000 g/L\times 1 L = 1000 g$

Volume of alcohol = 2.5 L

Density of alcohol = $789 kg/m^3=\frac{789000 g}{1000 L}=789 g/L$

Mass of alcohol = $789 g/L\times 2.5 L = 1972.5 g$

Mass of mixture = 1000 g + 1972.5 g = 2972.5 g

Mass percentage of water :

$\frac{1000 g}{2972.5 g}\times 100=33.64\%$

Mass percentage of alcohol :

$\frac{1972.5 g}{2972.5 g}\times 100=66.36\%$

Moles of water :

$n_1=\frac{1000 g}{18 g/mol}=55.55 mol$

Moles of alcohol =

$n_2=\frac{1972.5 g}{46 g/mol}=42.88 mol$

Mole fraction of water :

$\chi_1=\frac{n_1}{n_1+n_2}=\frac{55.55 mol}{55.55 mol+42.88 mol}=0.5644$

Mole fraction of alcohol :

$\chi_2=\frac{n_2}{n_1+n_2}=\frac{42.88 mol}{55.55 mol+42.88 mol}=0.4356$

3 0

3 years ago

Trick to change word equation to chemical equation

Elden [556K]

Answer:

actually word equation has the names and we need to write molecular formula in chemical eqn. so I don't think there is sort of trick.You just need to memorise the molecular formula of chemicals.

6 0

3 years ago

Definition plz someone plz plz plz

lubasha [3.4K]

Force: any interaction that, when unopposed, will change the motion of an object.

Mass: the quantity of matter in a body regardless of its volume or of any forces acting on it

Acceleration: rate of change of velocity of an object with respect to time

5 0

3 years ago