There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer:
234.784 ~ 235
Step-by-step explanation:
One side = 210
other side = 105
a2+b2 = c2
210 ^2 + 105 ^2 = c2
55125 = c ^2
c =
= 234.784 ~ 235
hope its right!!!
Answer:
Step-by-step explanation:
15x-35x
25x is the answer
Answer:
(0 , 3)
Step-by-step explanation:
simplify the equation
y =
x + 3