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3 years ago

6 = m/8 M=? What is the answer for M?

Mathematics

1 answer:

galben [10]3 years ago

6 0

Answer:

m =48

Step-by-step explanation:

1st step is to multiply both sides by 8

2nd step it would be 48=m

3rd step swap the sides.. m=48

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drag statements and reasons to each row to show why the slope of the line between r and s is the same as the slope between s and

serg [7]

Sorry this came pretty late but I just answered the question and thought it might help someone else later

Answer:

6 0

3 years ago

Read 2 more answers

The value of y varies directly as x with a constant variation of 2 what is the value of y when x is 6?

sp2606 [1]

Answer:

The value of y is 12

Step-by-step explanation:

y∝x

y = kx

y = 2x

when x = 6, y = 2(6)

= 12

(Correct me if i am wrong)

8 0

3 years ago

For each of the following pairs of signed integers (2’s complement), subtract the second from the first. Show the decimal equiva

Dmitry_Shevchenko [17]

Answer:

The answers are

a)111010 - 001111 = 101011 = 43

b) 000100 - 011000 = 111111111 (overflow) = -20

c) 010001 - 011010 = 11111111 (overflow) = -9

d) 010000 - 100100 = 1111111 (overflow) = -20

Step-by-step explanation:

a)111010 = 1×2⁵+1×2⁴+1×2³+0×2²+1×2¹+0×2⁰ = 32+16+8+0+2+0= 58

001111 = 0×2⁵+0×2⁴+1×2³+1×2²+1×2¹+1×2⁰ = 8+4+2+1=15

111010 - 001111 = 101011 = 43

b) 000100 = 0×2⁵+0×2⁴+0×2³+1×2²+0×2¹+0×2⁰ = 4

011000 = 0×2⁵+1×2⁴+1×2³+0×2²+0×2¹+0×2⁰ = 24

000100 - 011000 = 1111111111 (overflow), 4 - 24 =-20

c) 010001 = 1×2⁴+1×2⁰ = 17

011010 = 1×2⁴+1×2³+1×2¹ = 26

010001 - 011010 = 11111111 (overflow) 17-26=-9

d) 010000 = 1×2⁴ = 16

100100 = 1×2⁵+1×2² = 36

010000 - 100100 = 1111111 (overflow) 16-36=-20

3 0

3 years ago

Which of the following statements are true regarding functions?

stich3 [128]

Answer: D and A

Step-by-step explanation:

Just took the apex quiz and it’s right

3 0

3 years ago

Solve the simultaneous equation y-2x+1=0 and 4x^2+3y^2-2xy=7

Lapatulllka [165]

The first equation is $y-2x+1=0$

$y=2x-1$ (Equation 1)

The second equation is $4x^{2}+3y^{2}-2xy=7$ (Equation 2)

Putting the value of x from equation 1 in equation 2.

we get,

$4x^{2}+3(2x-1)^{2}-2x(2x-1)=7$

$4x^{2}+3(4x^{2}+1-4x)-4x^{2}+2x=7$

by simplifying the given equation,

$12x^{2}-10x-4=0$

$6x^{2}-5x-2=0$

Using discriminant formula,

$D=b^{2}-4ac$

$D=25-4 \times 6 \times -2 = 73$

Now the formula for solution 'x' of quadratic equation is given by:

$x=\frac{-b+\sqrt{D}}{2a} and x=\frac{-b-\sqrt{D}}{2a}$

$x=\frac{5+\sqrt{73}}{12} and x=\frac{5-\sqrt{73}}{12}$

Hence, these are the required solutions.

8 0

3 years ago