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Afina-wow [57]
2 years ago
15

A moving sidewalk travels at a rate defined by the function f(x). A boy on the sidewalk is walking at a rate defined by the func

tion g(x). The sum of the functions, h(x), represents the rate he is moving relative to his surroundings. Which could be the graph of the functions?

Mathematics
1 answer:
tatiyna2 years ago
6 0
The answer is :
B.


Ex- hope this helps!
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The distance between -18 and 15 is equal to _____. 18 - 15 15 - 18 -18 - 15 15 - (-18)
NemiM [27]

Answer: Choice D.  15 - (-18)

This results in 15 - (-18) = 15 + 18 = 33.

So from -18 to 15 on a number line is 33 spaces.

We can also say

|-18 - 15| = |-33| = 33

The use of absolute value is to ensure the distance is never negative.

5 0
3 years ago
Not the best at this! Can someone please help me ?!
umka2103 [35]

Answer:

1= 2x+11

2= is none of those

3= √x^2 –11

4= √2x+11

Step-by-step explanation:

5 0
2 years ago
A realtor earns 1.25%commision on the price of any home she sells last month she sold two homes for a total of $750,000. How muc
TEA [102]

Answer: total amount of money in commission that the realtor earned is $9375

Step-by-step explanation:

The realtor earns 1.25% commission on the price of any home she sells.

Last month she sold two homes for a total of $750,000

It means that the amount of money in commission that the realtor earned last month would be

1.25/100 × 750 000 = 0.0125 × 750000 = $9375

4 0
3 years ago
Read 2 more answers
Find the quotient 5/28 divided by 1/7
VARVARA [1.3K]

Answer:

1.25

Step-by-step explanation:

4 0
3 years ago
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p varies jointly as q and the square of r, and p = 200 when q = 2 and r = 3. Find p when q = 5 and r= 2.
Margarita [4]

Step-by-step explanation:

If a variables varies jointly, we can just divide it by the other variables in relation to it.

For example, since p variables jointly as q and square of r, then

\frac{p}{q {r}^{2} }  = k

where k is a constant

First, let find k. Substitute p= 200

q= 2, and r=3.

\frac{200}{2(3) {}^{2} }  = k

\frac{200}{18}  = k

\frac{100}{9}  = k

Now, since we know our constant, let find p.

\frac{p}{q {r}^{2} }  =  \frac{100}{9}

Q is 5, and r is 2.

\frac{p}{5( {2}^{2}) }  =  \frac{100}{9}

\frac{p}{20}  =  \frac{100}{9}

p =  \frac{2000}{9}

3 0
1 year ago
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