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Virty [35]
3 years ago
9

What is 24.84 in simplest radical form​

Mathematics
1 answer:
Bogdan [553]3 years ago
8 0

Answer:

5 than square root over 10

Step-by-step explanation:

because when you write it out you recive this answer

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please ANSWER at least ONE question CORRECTLY FOR 8 POINTS & ANSWER at least THREE CORRECTLY to be MARKED BRAINLIEST! (you d
4vir4ik [10]

Answer:

a. yes

b. no

c. no

d. no

e. yes

Step-by-step explanation:

Here, we want to answer yes or no for each of the numbers

a) Yes

If we compare with the general form

y = mx + b

m

is slope and b is y-intercept

so, 2 is slope and 3 is y intercept; so 3 in y-intercept is (0,3)

b. No

This is the point-slope form we are trying to

get

Evaluating this, we have that

y-3 = 2x - 6

y = 2x-6 + 3

y = 2x-3

c) NO

Just insert the values and check here

-1 = 2(5) + 3

it does not work

d) No

Substitute

-4 = 2(-5) + 3

e) Yes

This is the point-slope form

y + 3 = 2x + 6

y = 2x + 6-3 = 2x + 3

8 0
3 years ago
I NEED HELPPP PLEASE!!
yaroslaw [1]

Answer:

226 tons of seed......

5 0
3 years ago
PLEASE help with this question
Tema [17]

Answer:

option A

12m/s

Step-by-step explanation:

Given in the question,

mass of object = 11kg

kinetic energy possess by = 792 joules

To find the velocity we use formula

v =  \sqrt{\frac{2KE}{m} }

Plug values in the formula

v = \sqrt{\frac{2(792)}{(11)} }

v = \sqrt{\frac{1584}{11} }

v = \sqrt{144}

v= 12 m/s

3 0
4 years ago
What is a ratio equal to 8 to 12
olga2289 [7]
In simplest form (smallest possible answer) the ratio is equal to 2:3. But it is also equal to 4:6.
4 0
3 years ago
An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e
uranmaximum [27]

Answer:

<em>The answers are for option (a) 0.2070  (b)0.3798  (c) 0.3938 </em>

Step-by-step explanation:

<em>Given:</em>

<em>Here Section 1 students = 20 </em>

<em> Section 2 students = 30 </em>

<em> Here there are 15 graded exam papers. </em>

<em> (a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070 </em>

<em> (b) Here if x is the number of students copies of section 2 out of 15 exam papers. </em>

<em>  here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15 </em>

<em>Then, </em>

<em> Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798 </em>

<em> (c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1) </em>

<em> so, </em>

<em> Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938 </em>

<em> Note : Here the given distribution is Hyper-geometric distribution </em>

<em> where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>

7 0
3 years ago
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