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2 years ago

Find the general solution of the given differential equation x2 y’ -2xy = x4 + 3

Mathematics

1 answer:

Contact [7]2 years ago

5 0

$\times 2 \: y \: - 2xy = \times 4 + 3 = \times - \frac{3}{4} \: y \: e \: r$

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Which of the following equations is equivalent to 2 + x + 2x = 14? A 4X E 14 B 3x = 12 C 3x = 16 D 1x = 12

Alex_Xolod [135]

Step-by-step explanation:

2 + x + 2x = 14

3x + 2 = 14 (combine like terms)

3x = 12 (subtract 2 from both sides)

Hence the answer is 3x = 12. (B)

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3 years ago

- f(x) = 4(x + 3)2 +1<br>Find f(-9).<br>

Xelga [282]

my answer is -24

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2 years ago

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Write an equation that models this situation.

Nimfa-mama [501]

Answer:

Step-by-step explanation:

the ideal way to put the equation would be x= 6 x 8 but since that is not an option B is the answer. the keyword is "each" that allows you to know that you will be multiplying those to numbers.

so the only one that allows you to multiply 6 and 8 is B when you multiply 6 to the other side.

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2 years ago

The revenue, in dollars, of a company that produces jeans can be modeled by 2x2 + 17x – 175. The cost, in dollars, of producing

PolarNik [594]

Hello,

P(x)=20x-50
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3 years ago

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Three numbers form a geometric progression. If the second term is increased by 2, the progression will become arithmetic and if,

Evgesh-ka [11]

In this exercise we have to use the knowledge of geometric progression to find three specific numbers, in this way we can say that these numbers correspond to;

$0.16\\ -0.64\\ 2.56$

Then using the formula of the geometric progression we find that:

$a_1*r = a_2\\a_2*r = a_3 = a_1*r^2$

now, the differences between the terms must be the same:

$a1*r + 2 - a_1 = a_3 - (a_1*r + 2) = a_1*r^2 - (a_1*r + 2)\\a_1*r^2 - 2*a_1*r + a_1 - 4 = 0$

and now, when we increase the third term by 9,so we have:

$(a_1*r^2 + 9)/(a_1*r + 2) = (a_1*r + 2)/a_1\\(a_1^2*r^2 + 9*a_1)/(a_1*r + 2) = a_1*r + 2\\a_1^2*r^2 + 9*a_1 = (a_1*r + 2)^2 = a_1^2*r^2 + 4*a_1*r + 4\\4*a_1*r - 9*a_1 + 4 = 0\\9*a - 4 = 4*a_1*r\\r = (9*a_1 - 4)/(4*a_1)$

Now we use that identity in the first equation :

$a_1*(9*a_1 - 4)^2/(4×a_1)^2 - 2*a_1*(9*a_1 - 4)/(4*a_1) + a_1 - 4 = 0\\(81*a_1^2 - 72*a_1 + 16)/(16*a_1) - (9*a_1 - 4)/2 + a_1 - 4 = 0\\81*a_1^2 - 72*a_1 + 16 - 8*a_1*(9*a_1 - 4) + 16*a_1^2 - 64*a_1 = 0\\25a_1^2 - 104a_1 + 16 = 0$