ok well first you would find what the square root would be then you just see where it falls on the number line
so the sqrt of 29 is 5.38516... so it falls between 5 and 6.
so the answer is 5 and 6
Answer:
136
Step-by-step explanation:
h(x)=4(5x-1)
substitute 7 for x
h(7)=4(5(7)-1)
*****Remember PEMDAS*****
=4(35-1)
=4(34)
h(7)=136
Answer:
1 and 2/10
Step-by-step explanation:
<u>Given</u>:
Two cylinders are similar. The volume of one is 64 cm³ and the volume of the other is 729 cm³.
We need to determine the scale factor between them.
<u>Scale factor:</u>
Since, it is given that the volume of two cylinders, we need to take cube root.
Thus, we have;
![Scale \ factor=64:729](https://tex.z-dn.net/?f=Scale%20%5C%20%20factor%3D64%3A729)
Taking cube root, we get;
![Scale \ factor=\sqrt[3]{64} :\sqrt[3]{729}](https://tex.z-dn.net/?f=Scale%20%5C%20%20factor%3D%5Csqrt%5B3%5D%7B64%7D%20%3A%5Csqrt%5B3%5D%7B729%7D)
Simplifying, we have;
![Scale \ factor=4:9](https://tex.z-dn.net/?f=Scale%20%5C%20%20factor%3D4%3A9)
Thus, the scale factor between the two cylinders is 4 : 9
There are two sets of Y values identical ( 0 and 5 ).
There are two sets of identical X values ( -1 and 2)
This makes a rectangle.
The length is 5-0 = 5
The width is 2 - -1 = 3
Area = Length x width = 5 x 3 = 15 square units.