All categories

3 years ago

4 (2r + 3 ) = 15r - 11 +1 - 7r

Mathematics

2 answers:

KiRa [710]3 years ago

7 0

delete this

boop uwu

marissa [1.9K]3 years ago

3 0

Answer:

<em>No solutions</em>

Step-by-step explanation:

4(2r + 3) = 15r - 11 + 1 - 7r

Distribute:

8r + 12 = 15r - 11 + 1 - 7r

Combine like terms:

8r + 12 = 8r - 10

Same to both sides:

0r = -22

<em>No solutions</em>

You might be interested in

A women has twice as many dimes as quarters in her purse.If the dimes were quarters and the quarters were dimes,she would have $

skad [1K]

2.98 i think dont come for if it not ok

3 0

3 years ago

In a recent semester at a local university, 490 students enrolled in both General Chemistry and Calculus I. Of these students, 6

posledela

I think its 149/ 490. Not sure, but pretty confident. Hope this helps.

8 0

3 years ago

Assume that T is a linear transformation. Find the standard matrix of T. T: R^3 right arrow R^2 , T(e 1) =(1,2), and T(e2 ) =( -

irina [24]

Answer:

$A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]$

Step-by-step explanation:

Given

$T:R^3->R^2$

$T(e_1) = (1,2)$

$T(e_2) = (-4,6)$

$T(e_3) = (2,-6)$

Required

Find the standard matrix

The standard matrix (A) is given by

$Ax = T(x)$

Where

$T(x) = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]$

$Ax = T(x)$ becomes

$Ax = [T(e_1)\ T(e_2)\ T(e_3)]\left[\begin{array}{c}x_1&x_2&x_3\\-&&x_n\end{array}\right]$

The x on both sides cancel out; and, we're left with:

$A = [T(e_1)\ T(e_2)\ T(e_3)]$

Recall that:

$T(e_1) = (1,2)$

$T(e_2) = (-4,6)$

$T(e_3) = (2,-6)$

In matrix:

$(a,b)$ is represented as: $\left[\begin{array}{c}a\\b\end{array}\right]$

So:

$T(e_1) = (1,2) = \left[\begin{array}{c}1\\2\end{array}\right]$

$T(e_2) = (-4,6)=\left[\begin{array}{c}-4\\6\end{array}\right]$

$T(e_3) = (2,-6)=\left[\begin{array}{c}2\\-6\end{array}\right]$

Substitute the above expressions in $A = [T(e_1)\ T(e_2)\ T(e_3)]$

$A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]$

Hence, the standard of the matrix A is:

$A = \left[\begin{array}{ccc}1&-4&2\\2&6&-6\end{array}\right]$

6 0

3 years ago

What is the value of the expression (9+15)/3+2?

KIM [24]

(9+15)/3+2
24/3+2
8+2
10

6 0

3 years ago

Read 2 more answers

Paul deposits $5000 in a bank which pays a compound interest rate of 5% per

disa [49]

Answer:

$4866.61

Step-by-step explanation:

3 0

3 years ago