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Verdich [7]
3 years ago
13

4 (2r + 3 ) = 15r - 11 +1 - 7r

Mathematics
2 answers:
KiRa [710]3 years ago
7 0

delete this

boop uwu

marissa [1.9K]3 years ago
3 0

Answer:

<em>No solutions</em>

Step-by-step explanation:

4(2r + 3) = 15r - 11 + 1 - 7r

Distribute:

8r + 12 = 15r - 11 + 1 - 7r

Combine like terms:

8r + 12 = 8r - 10

Same to both sides:

0r = -22

<em>No solutions</em>

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The reaction is missing and it's ;

N2H4 + H2 ---> 2NH3

It asks for the total pressure too.

Answer:

A) Rate of change for NH3 = 152 torr/h

B) The total pressure in the vessel will remain the same.

Step-by-step explanation:

N2H4 + H2 ---> 2NH3

1 mole of N2H4 yields 2 moles of NH3.

From the question, the rate given for N2H4 is 76 torr/h.

Thus, The rate of change for NH3 will be = 2 x 76 = 152 torr/h

Now, on the reaction side, 1 mole of N2H4 reacts with 1 mole of H2. So we have 2 moles on the left hand side.

While on the product side, 2 moles of NH3 are produced.

So the total pressure will remain the same because for every 2 moles on the reaction side, 2 moles are gotten on the product side.

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