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Lubov Fominskaja [6]
3 years ago
5

Cada caja contiene el mismo número de cuadernos. Si Mario transporta 120 cuadernos en total en una carretilla, ¿cuántos cuaderno

s habrá en 120 cajas iguales?
Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0

Answer:

Se almacena un cuaderno por caja, significando 120 cuadernos en 120 cajas iguales.

Step-by-step explanation:

A partir del enunciado, podemos calcular el número de cuadernos por caja al dividir el total de cuadernos en la carretilla por el número de cajas disponibles.

x = \frac{120\,cuadernos}{120\,cajas}

x = 1\,\frac{cuadernos}{caja}

Se almacena un cuaderno por caja, significando 120 cuadernos en 120 cajas iguales.

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Step-by-step explanation:

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22. Mona is in her garden jumping on stones (as shown below).
iris [78.8K]

\large\green{\sf\boxed{Given:-}}

<u>Mona starts from 68th stone</u>

<u>She jumps</u><u> </u><u>23</u><u> </u><u>stones</u><u> </u><u>ahead</u><u> </u>

<u>Then</u><u> </u><u>she</u><u> </u><u>jumps</u><u> </u><u>28</u><u> </u><u>stones</u><u> </u><u>back</u>

\large\red{\sf\boxed{To \:find:-}}

<em>Her final position=?</em>

\large{|\underline{\mathtt{\red{S}\blue{o}\orange{l}\pink{u}\blue{t}\purple{i}\green{o}\red{n}\blue{:}\orange{-}}}}

  • Add 23 in 68 [Given]

\begin{gathered}\\ \sf\longmapsto 68+23=91\end{gathered}

  • Subtract 28 from 91

\begin{gathered}\\ \sf\longmapsto 91-28=Her\:final\:position\end{gathered}

\begin{gathered}\\ \sf\longmapsto =63\end{gathered}

  • To find how much stones she is ahead or back we will Subtract 63 from 68 which was her initial position.

\begin{gathered}\\ \sf\longmapsto 68-63=5\end{gathered}

So, Mona will be <em><u>5</u></em><em><u> </u></em><em><u>stones</u></em><em><u> </u></em><em><u>behind</u></em><em><u> </u></em><em><u>from</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>starting</u></em><em><u> </u></em><em><u>stone</u></em><em><u>.</u></em>

☯️Hence, Option C is correct

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Answer:

d, a, e, c, b

Step-by-step explanation:

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