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myrzilka [38]
3 years ago
5

I need help! Please and thank you

Mathematics
2 answers:
larisa [96]3 years ago
7 0
I don’t know sorry I will come back to this :(
pashok25 [27]3 years ago
4 0
2 3/8

Add 1 1/8 and 1 1/4 together and you get 2.375
0.375 as a fraction is 3/8 so 2 3/8
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Please help asap!!! Will give brainleist for the right answer
Solnce55 [7]

Answer:

I think the answer is 1,032 pounds

Step-by-step explanation:

You would have to multiply the dimensions of the table first:

8*3*1=24.

Then you would multiply that by 43.

24*43=1,032.

I THINK this is the answer.

5 0
3 years ago
Mary runs 4 laps in 8 mins. Nicole runs 12 laps in 18 mins. Who runs faster
Georgia [21]
Find to LCM of 8 and 18 to compare times

Mary: 4*9laps/8*9min
36 laps/ 72 mins
Nicole: 12*4laps/18*4 mins
48 laps/ 72 mins

Nicole runs more laps in the same amount of time as Mary

Therefore, Nicole runs faster
6 0
3 years ago
56 divided (-10)<br><br> What is the answer?
ElenaW [278]

Answer:

-5.6

Step-by-step explanation:

56/-10 = -5.6

5 0
3 years ago
Find two numbers, if their sum is −11 and their difference is 41
snow_tiger [21]

The larger one is (-11 + 41)/2 = 15.

The smaller one is (-11 -41)/2 = -26.

_____

For two numbers a and b with sum s and difference d, you can write the equations

a+b=s\\a-b=d

Then adding the equations and dividing that sum by 2, you get

(a+b)+(a-b)=(s)+(d)\\2a=s+d\\a=\dfrac{s+d}{2}

You can subtract the second eqution from the first and get a similar result for the smaller number

(a+b)-(a-b)=(s)-(d)\\2b=s-d\\b=\dfrac{s-d}{2}

These are the formulas we used above.

3 0
4 years ago
Escherichia coli cells are about 2.65 μm long and 0.480 μm in diameter. Calculate the volume of an E. coli cell, assuming the ce
zmey [24]

Answer:

4.7953 x 10⁻¹⁹ m³

Step-by-step explanation:

Length of the Escherichia coli cell (L) = 2.65 x 10⁻⁶ m

Diameter of the Escherichia coli  cell (D) = 0.480 x 10⁻⁶ m

The volume of cylinder in given by:

V= \frac{\pi D^2}{4}*L \\V= \frac{\pi (0.480*10^{-6})^2}{4}*2.65*10^{-6}\\V= 4.7953*10^{-19} m^3

The volume of an E. coli cell is 4.7953 x 10⁻¹⁹ m³.

6 0
3 years ago
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