Going down the chart:
6
4
3
4
6
the brackets on the outside of the lxl makes the value positive or keeps the value positive. therefor if u have y=l-3l+3 y will still =6! hope this helps!
Well obviously quarters equal 25 cents. So you have to divide the 8.85 by 25 first. That means he could have 35 quarters. That least the rest as being dimes. So find the remaining amount of the 8.85. If you have 35 quarters that's $8.75. And 8.85 minus 8.75 is 10 cents. which would be 2 nickels. That only adds up 37 coins. So you break down one of the 25. That would mean 5 more coins could be nickels. Add 37 and 5 to get 42. Do it again. 25 cents in nickels would be 5 more coins. would be 46. that would be missing 2 coins. But don't forget you're also subtracting from the 35 quarters. Now you would technically have 12 nickels and 33 quarters. So you can do it one more time. 32 quarters means there is $8 in quarters at this point.
Now add you have 12 nickels, and you made 5 more. That's 17 nickels. That equals 85 cents. So add 17 and 32 to be sure you have 49 coins, which you do.
So 17 nickels, 32 quarters to equal 49 coins and $8.85
(sorry some of it got mixed up above because I was forgetting to subtract the quarters from the total as I changed them to nickels, so pay attention to the end)
Answer:
CD = √11 and CE = √11
Step-by-step explanation:
We know that m∠D is 45° (by using the sum of interior angles in a triangle) so therefore, ΔDCE is a 45 - 45 - 90 triangle (the 45, 45, and 90 refer to the angle measures). The ratio of sides in a 45 - 45 - 90 triangle is 1 : 1 : √2 where the 1s are the sides and the √2 is the hypotenuse. We need to solve for x in x : x : √22. If you notice that √22 = √2 * √11, we can use this to find x, therefore, x = 1 * √11 = √11 so CD = √11 and CE = √11.
Answer:
i think 64 for your answer
Step-by-step explanation:
Answer:
Part a) The area of the swimming pool is 
Part b) The total area of the swimming pool and the playground is 
Step-by-step explanation:
Part a) Find the area of the swimming pool
we know that
The area of the swimming pool is
where
L is the length side
W is the width side
we have
substitute the values
therefore
The area of the swimming pool is
Part b) The area of the playground is one and a half times that of the swimming pool. Find the total area of the swimming pool and the playground
we know that
To obtain the area of the playground multiply the area of the swimming pool by one and a half
To obtain the total area of the swimming pool and the playground, adds the area of the swimming pool and the area of the playground
so
therefore
The total area of the swimming pool and the playground is
