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2 years ago

HELP PLEASE ASAP

Mathematics

1 answer:

3241004551 [841]2 years ago

5 0

Answer:

c. 1/4 x 40

Step-by-step explanation:

25% = 1/4

so the most logical option would contain 1/4, which is c.

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Using the transformation T: (x, y) (x + 2, y + 1), find the distance named. Find the distance BB'

AnnZ [28]

Answer:

$\sqrt{5}\ units$

Step-by-step explanation:

we know that

The rule of the translation is equal to

$(x,y)-----> (x+2,y+1)$

That means

The translations is $2$ units to the right and $1$ unit up

Let

$(x,y)$ -------> the coordinates of point B

$(x+2,y+1)$ ------> the coordinates of point B'

Find the distance

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute

$d=\sqrt{((y+1)-y)^{2}+((x+2)-x)^{2}}$

$d=\sqrt{(1)^{2}+(2)^{2}}$

$d=\sqrt{5}\ units$

8 0

2 years ago

Read 2 more answers

Put the following equation of a line into slope-intercept form, simplifying all fractions.

baherus [9]

Answer: y=-3/2x+3

Step-by-step explanation:

First subtract 3x from both sides to start isolating the y.

Then you get 2y=-3x+6

Divide both sides by 2 to get y alone and you get

y=-3/2x+3

5 0

2 years ago

Read 2 more answers

Some angles are shown. Complete each of the 2 activities for this Task. Activity 1 of 2 The measure of angle NOP is 140°. Which

garik1379 [7]

Answer:

A. 23+x=140

Step-by-step explanation:

The angle addition postulate states that the measure of a larger angle formed by two or more smaller angles placed side by side is the the sum of the smaller angles. The angle addition postulate states that if B is in the interior of AOC , then:

m∠AOB + m∠BOC = m∠AOC.

From the image:

∠NOP = ∠NOQ + ∠QOP

∠NOP = 140, ∠NOQ = x, ∠QOP = 23

substituting:

140 = x + 23

x = 140 - 23 = 117

∠NOQ = 117°

6 0

2 years ago

Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2

Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

7 0

2 years ago

6) The amount of Jen's monthly phone bill is normally distributed with a mean of $70 and a standard

alexandr402 [8]

Answer:

i)The correct option is D.) 99.74%

ii) The correct option is B.) 68.26%

Step-by-step explanation:

i) P(10≤X≤70) = P( (10−40)/10 ≤Z≤ (70−40 )/10 ) = Pr(−3≤Z≤3)

= 0.9987 - 0.0013 = 0.99734

Therefore the percentage of Jen's monthly phone bills are between $40 and $100 is D.) 99.74%

ii)P(2.1≤X≤3.1) = P( (2.1 − 2.6) /0.5 ≤ Z ≤ (3.1−2.6 )/0.5) = Pr(−1 ≤Z ≤1) )

= 0.8413 − 0.1587 = 0.6826

Therefore the percentage of students at college have a GPA between 2.1 a,d 3.1 is B.) 68.26%

5 0

2 years ago