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3 years ago

HELP PLEASE ASAP

Mathematics

1 answer:

3241004551 [841]3 years ago

5 0

Answer:

c. 1/4 x 40

Step-by-step explanation:

25% = 1/4

so the most logical option would contain 1/4, which is c.

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Suppose you have to use right-triangle trigonometry to find the apothem of a regular polygon. Which is greater, the apothem or t

asambeis [7]

The apothem represents one side of the right triangle to be solved. Specifically, it represents the height of the triangle.
The radius of the polygon represents the hypotenuse of the right triangle that is going to be solved.
Therefore, we can infer that the radius of the polygon is greater than the apothem because the hypotenuse is greater than all sides of a triangle.
Answer:
the radius of the polygon is greater

8 0

3 years ago

What is the equation of the line that passes through the points (1,5) and (0,3)?

Pavlova-9 [17]

Answer:

y=2x+3

Step-by-step explanation:

first use the y2-y1/x2-x1 then use y=mx+b after

plug in 3 for y2 and 5 for y1

then plug in 0 for x2 and 1 for x1

$\frac{3-5}{0-1}$ = $\frac{-2}{-1} =2$ and 2 is ur slope

___________________

now use y=mx+b

i usually use the first point but u can u anyone u want

plug in 1 for x

plug in 5 for y

and plug in 2 for m

5=2(1)+b

5=2+b

subtract 2 on both sides

5-2=3

3=b and b is ur y-intercept

y=2x+3

hope this helps

4 0

3 years ago

4[( 8 + 4)10] + 24 devided by 2^3

Nikolay [14]

4[(8+4)10] + 24
so 8 + 4 is 12. Multiply that by 10 and that's 120.
120 + 24 is 144
144 × 4 is 576
for "devided by 2^3" do you mean divided by 2/3?
If so then its 576 ÷ 2/3 = 96

8 0

3 years ago

Find the product.

tankabanditka [31]

the answer would be c

8 0

3 years ago

Read 2 more answers

D(x)=(x^2-12x+20)/(3x)

krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

Explanation:

d(x) = $\frac{x^{2}-12x+20}{3x}$

= $\frac{(x-2)(x - 10)}{3x}$

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0

÷3 ÷3

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

(1/3)x - 4
3x) x² - 12x + 20
x²
-12x
-12x
20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4

6 0

3 years ago