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Flauer [41]
3 years ago
6

A high school student hires a trainer to help him get ready for football season. The trainer charges $100 plus $75 an hour for e

ach hour he works with the student. How many hours does the trainer have work to make more than $625
Mathematics
2 answers:
Naddika [18.5K]3 years ago
8 0

Answer: i think 4 hours

Step-by-step explanation:

Ghella [55]3 years ago
6 0

Answer:

4 hours

Step-by-step explanation:

So 100 + 75 is 175 so just add 175 until you get to a number that’s higher than 625

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3 years ago
HELP PLZZ will give brainliest &lt;3
melisa1 [442]

Answer:

0

1

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

\dfrac{a}{\sin A} = \dfrac{b}{\sin B}

\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}

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Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

\dfrac{b}{\sin B} = \dfrac{c}{\sin C}

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\sin C = \dfrac{8.9\sin 63^\circ}{10}

C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}

C \approx 52.5^\circ

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

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Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

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creativ13 [48]
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