Let the number of bike be x and the number of skates be y, then
21x + 20y ≥ 362 . . . (1)
2y = x . . . (2)
Putting (2) into (1), then
21(2y) + 20y ≥ 362
42y + 20y ≥ 362
62y ≥ 362
y ≥ 5.84
The least number of pairs of skates they need to rent each day to make their minimum is 6.
Okay so i cant just post what the answer is i have to type something.
but anyways this is the answer: t= 4.56
260 was its original prize.
To get the that relates x and y, we choose two points on the table and use the equation of a straight line as follows:
Recall that the equation of a staight line is obtained from the formula

Using the points (30, 18) and (36, 24), we have