Question

Factor this trinomial completely. 2x2 + 6x + 4 O

Answer 1

Answer:

B.  2(x+2)(x+1)

Step-by-step explanation:

Answer 2

$\sf\purple{B. \:2(x + 2)(x+1) }$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$2 {x}^{2} + 6x + 4$

Taking 2 as common factor, we have

$= 2 \: ( {x}^{2} + 3x + 2) \\ =2 \: ( {x}^{2} + 2x + x + 2)$

Taking $x$ as common from first two terms and 1 from last two terms, we have

$= 2 \:[x(x + 2) + 1(x + 2)]$

Taking the factor $(x+2)$ as common,

$= 2(x + 2)(x + 1)$

$\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}$