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olasank [31]
3 years ago
13

I also really need help with this question! g(x)=2x - 3 h(x)=2x + 4 Find (g/h)(x)

Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0
(2x-3)/(2(x+2))
x cannot equal -2
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Which of the following topics would lend itself only to a formal style of writing?
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D because its more formal then the other ones.
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4 years ago
Give a summary of the lesson what you have learned. about EXPONENTS!!​
DochEvi [55]
The exponent tells us how many times to multiply a base to itself. The base is, of course, the thing that's being multiplied. When we use exponents, we call it "raising to a power". The power equals to the exponent, so in our example, x is raised to a power of 4.


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Learning about exponents helps students think about and understand expressions. ... Identify when two expressions are equivalent (i.e., when the two expressions name the same number regardless of which value is substituted into them).
8 0
3 years ago
Which of the following is equivalent to (1/2)^-2t
Zepler [3.9K]

Answer:

Choice (3) \left(2^2\right)^t is correct.

Step-by-step explanation:


Given expression is \left(\frac{1}{2}\right)^{-2t}

Now we need to simplify this and check which of the given choices best match with it.

\left(\frac{1}{2}\right)^{-2t}

=\left(\frac{1}{2^1}\right)^{-2t}

=\left(2^{-1}\right)^{-2t} {using formula =\frac{1}{x^m}=x^{-m}}

=\left(2^{-1}\right)^{-2t} {using formula =\left(x^m\right)^n=x^{\left(m\cdot n\right)}}

=2^{\left(-1\right)\left(-2t\right)}

=2^{2t}

=\left(2^2\right)^t {using formula =\left(x^m\right)^n=x^{\left(m\cdot n\right)}}

Hence choice (3) \left(2^2\right)^t is correct.

8 0
3 years ago
Read 2 more answers
Rearrange x=3g+2 to make g the subject.
mina [271]
We have: x = 3g + 2

Subtract 2 from the both sides, 
x - 2 = 3g + 2 - 2
x - 2 = 3g

Now, Divide 3 from both sides, 
(x-2)/3 = 3g/3
g = x-2 / 3

In short, Your Answer would be x-2 /3

Hope this helps!

6 0
3 years ago
Read 2 more answers
Solve the inequality, show your work, and graph is on the number line
Dennis_Churaev [7]
Download got it and see if it answers faster
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4 years ago
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