Answer:
Step-by-step explanation:
given are the two following linear equations:
f(x) = y = 1 + .5x
f(x) = y = 11 - 2x
Graph the first equation by finding two data points. By setting first x and then y equal to zero it is possible to find the y intercept on the vertical axis and the x intercept on the horizontal axis.
If x = 0, then f(0) = 1 + .5(0) = 1
If y = 0, then f(x) = 0 = 1 + .5x
-.5x = 1
x = -2
The resulting data points are (0,1) and (-2,0)
Graph the second equation by finding two data points. By setting first x and then y equal to zero it is possible to find the y intercept on the vertical axis and the x intercept on the horizontal axis.
If x = 0, then f(0) = 11 - 2(0) = 11
If y = 0, then f(x) = 0 = 11 - 2x
2x = 11
x = 5.5
The resulting data points are (0,11) and (5.5,0)
At the point of intersection of the two equations x and y have the same values. From the graph these values can be read as x = 4 and y = 3.
Answer:
P(t)=30
Step-by-step explanation:
Plug in t=6 into the equation: P(t)=t^2-t
So P(t)= (6)^2-6
P(t)=36-6
P(t)=30
Answer:
FV=PV(1−d)^n
FV = 290(1-.132)^14
FV = 290(.868)^14
FV = 39.96 g
Step-by-step explanation:
Wait for area, wouldn't you just times 13 and 5 and get 65 and then times 23?
The answer is: D) 115
The explanation is shown below:
1. You have that the frequency with which a cricket chirps varies directly with the temperature, which you can express it as following:
Where 
is the frequency with which a cricket chirps, 
is the temperature and 
is the constant of proportionality.
2. If the cricket chirps 100 times per minute in 80° weather, you can calculate as below:
3. Therefore, the frequency in 92° weather is:
