2 years ago

Please help asap 20 pts

Mathematics

1 answer:

makkiz [27]2 years ago

3 0

Answer:

Step-by-step explanation:

For it to be parallel, the lines must have the same slope. So A and C are out. Basic math reveals that if you plug in (1, 8) for <em>(x, y)</em> you find B to be true.

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Solve for x: 4 over x equals 5 over 10

julsineya [31]

Answer:

x = 8,

Step-by-step explanation:

$\displaystyle \frac{4}{x} = \frac{5}{10}$ .

$x \ne 0$ for it is a denominator. Multiply both sides with the product of the two denominators: $10\;x$ :

$\displaystyle \frac{4}{x}\cdot (10\; x) = \frac{5}{10}\cdot (10\;x)$ .

$40 = 5\; x$ .

Multiply both sides by one over the coefficient of x:

$\displaystyle \frac{1}{5} \times 40 = \frac{1}{5}\times 5\; x$ .

$x = 8$ .

8 0

3 years ago

Read 2 more answers

Assume lim f(x)-6 and lim g(x)-9. Compute the following limit and state the limit laws used to justify the computation.

emmasim [6.3K]

Answer:

Step-by-step explanation:

<h3><u>some relevant limit laws</u></h3>

lim C = C where c is a constant.

lim( f(x) + g(x)) =lim f(x) + lim g(x)

lim( f(x)g(x)) =lim f(x) * lim g(x)

lim( cg(x)) =clim g(x)

lim( f(x)/g(x)) =lim f(x) / lim g(x) if lim g(x) is not equal to zero.

lim( f(x))^2 = (lim f(x) )^2

lim square root( f(x)) = square root(lim f(x) )

$\lim_{n \to 3} g(x) = 9\\\\\lim_{n \to 3} f(x) = 6\\\\ \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10} \\\\ = \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10}\\\\= \sqrt[3]{lim_{n \to 3}f(x) \times lim_{n \to 3}g(x) + 10}\\\\= \sqrt[3]{6 \times 9 + 10}\\\\= \sqrt[3]{64}$