Answer:
hope it helps u..........
Consider the function f(x) = 3x − 2. Select True or False for each statement. The y-intercept is 2. A True B False The x-interce
1 answer:
You might be interested in
Answer:
0.8665 = 86.65% probability that the sample mean would be at least $39000
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean $39725 and standard deviation $7320.
This means that
Sample of 125:
This means that
The probability that the sample mean would be at least $39000 is about?
This is 1 subtracted by the pvalue of Z when X = 39000. So
By the Central Limit Theorem
has a pvalue of 0.1335
1 - 0.1335 = 0.8665
0.8665 = 86.65% probability that the sample mean would be at least $39000
Answer:
0.216 = 0.6³
Step-by-step explanation:
using the rule of logarithms
• x = n ⇔ x =
0.216 = 3 ⇒ 0.216 =
Answer:
Sampson gains 3.967 kilograms from November to February.
Step-by-step explanation:
Given:
Actual Weight on November 15 = 2.49 kg
On December 15, he weighed 1020 grams more
Since 1000 grams = 1 kg
Weight on December 15 = 1020 grams = 1.2 kg
Hence Weight gained from November 15 to December 15 = 1.2 kg
On January 15, he had gained another 2200 grams
Weight on January 15 = 2200 grams = 2.2 kg
Hence Weight gained from December 15 to January 15 = 2.2 kg
On February 15, he had only gained 0.567 kilograms.
Weight on February 15 = 0.567 kg
Hence Weight gained from January 15 to February 15 = 2.2 kg
Total weight gained from November to February = Weight gained from November 15 to December 15 + Weight gained from December 15 to January 15 + Weight gained from January 15 to February 15
Total weight gained from November to February =
Hence Sampson gained total weight of 3.967 kg from November to February.