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3 years ago

Help me with this please

Mathematics

1 answer:

eimsori [14]3 years ago

5 0

Answer:

A= 7.667

B= 6.2

C= 9

D= 2

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3,2

That’s the answer

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Please help me please I really need help please help me

professor190 [17]

You just have to reflect it over the blue line, so if one point is 2 squares from the blue line then you will make it 2 squares away on the other side of the blue line. The y point will stay the same so they will be the same height

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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do

vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

$P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107$

Then,

$P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007$

c) In this case, the distribution is B(1200,0.01)

$P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924$

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

$P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366$

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3 years ago

Maths easy class 8 whoever gets it I will give u brainlist

asambeis [7]

Answer:

424 cm²

Step-by-step explanation:

The figure is composed of a square and a trapezium on top

A of square = 18² = 324 cm²

A of trapezium = $\frac{1}{2}$ h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ the parallel bases

Here h = 8, b₁ = 18 and b₂ = 7 , then

A = 0.5 × 8 × (18 + 7) = 4 × 25 = 100 cm²

Area of hexagonal park = 324 + 100 = 424 cm²

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3 years ago

dedylja [7]

Answer:

Step-by-step explanation:

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Help me with this please​

Help me with this please