V = u + at u = 2 a = -5 t = 1/2 what is the value of v ?

5x-1/5=7/3 Find The LCD That would eliminate the fractions

photoshop1234 [79]

Answer:

$x=\frac{7}{15}$

Step-by-step explanation:

$5x-\frac{1}{5} =\frac{7}{3}$

$5x - \frac{3}{15} = \frac{35}{15}$

$5x - \frac{3}{15} + \frac{3}{15} = \frac{35}{15} + \frac{3}{15}$

$5x=\frac{35}{15}$

$\frac{5x}{5} } =\frac{\frac{35}{15}}{5}$

$x=\frac{7}{15}$

7 0

2 years ago

Find the surface area of the prism L=13 W=7 H=4

Wewaii [24]

Answer:

342 units squared

Step-by-step explanation:

since this is a rectangular prism, all we have to do is multiply the values by one of the other values once and multiply that by 2

6 0

3 years ago

The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m

UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of $\bar X$ Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.7,3.7)$

Where $\mu=14.7$ and $\sigma=3.7$

Since the distribution of X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And we have;

$\mu_{\bar X}= 14.70$

$\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59$

4 0

3 years ago

Three moons are in the same circular orbit around a planet. The moons are each 120,000 kilometers from the surface of the planet

VladimirAG [237]

Answer:

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

MN is the diameter of the planet which is $MN = 60000$

AM and NC are the distance of moons from the surface of the planet.

$AM = NC = 120000$

Since, angle ABC is given as 90 degree, it means, line AC will pass from the diameter of the planet.

So, distance between moon A and moon C is =

$AC=AM + MN + NC$

$AC = 120000+ 60000+ 120000$

$AC = 300000$

Hence the distance between point A and point C is 300000 Km. : Answer

Hope it will help :)

8 0

3 years ago

MATH QUESTION ON SLOPESSSSSSS

alex41 [277]

I’m fairly sure it is the last one. But the pictures are hard to see. 3/2 is the slope and -1 is the y intercept. Find the point at (0,-1) , the y intercept. Then go up 3 and over 2 to find the next point

3 0

3 years ago