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JulijaS [17]
3 years ago
6

4.2kg of oranges are £8.76. How much does 2kg cost

Mathematics
2 answers:
seropon [69]3 years ago
8 0

Answer:

x = 4.17

Step-by-step explanation:

We can use a ratio to solve

4.2 k                  2 k

---------------- = ---------------

8.76                     x

Using cross products

4.2 * x = 2 * 8.76

4.2x =17.52

Divide by 4.2

x=4.17

zhuklara [117]3 years ago
5 0

Answer:

2kg cost £4.18

Step-by-step explanation:

4.2 kg of oranges cost £8.76

:. 1 kg of orange cost £8.76/4.2 = £2.09

2kg cost 2 × £2.09 = £4.18

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Which of the following is a compound event?
AlekseyPX

Answer:

Getting sum 6 when rolling two dice

6 0
2 years ago
Find the product of 8x93 using distributive property. Show the steps and the solution
lesya692 [45]

Explanation:

Distributive property: → a(b+c)=ab+ac

Multiply by the numbers from left to right.

93*8=744

Then, you can also divide into the numbers.

744/8=93

744/93=8

Product it's going to be multiply by the numbers, fractions, factors, and multiples.

Hope this helps!

Thanks!

Have a great day!

3 0
3 years ago
Read 2 more answers
Brandon is playing hide-and-seek with Katy and Tony. Katy is hiding 63 feet south of Brandon, and Tony is hiding due east of Kat
sergij07 [2.7K]

Answer:

60 feets

Step-by-step explanation:

Given that :

Using Pythagoras rule :

Hypotenus = sqrt(Adjacent^2 + opposite^2)

From the attached picture :

x² = 87^2 - 63^2

x^2 = 7569 - 3969

X^2 = 3600

Take the square root of both sides :

X = sqrt(3600)

X = 60 feets

Hence, Katy and Tony are 60 feets apart

6 0
3 years ago
Determine the average rate of change of the function between the given values of the variable. g(x)=2/x ; x=4, x=a
IrinaK [193]
Average rate of change implies the quotient f(4)-f(a)/4-a which equals (1/2-a/2)/4-a=(1-a)/(8-2a) on (4,a)
3 0
3 years ago
Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then
tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}

Compute the number of candies in the sixth jar as follows:

\text{Number of candies in the 6th jar}=\frac{63}{32}x\\

                                                    =\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42

Thus, the number of candies in the sixth jar is 42.

4 0
3 years ago
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