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JulijaS [17]
3 years ago
6

4.2kg of oranges are £8.76. How much does 2kg cost

Mathematics
2 answers:
seropon [69]3 years ago
8 0

Answer:

x = 4.17

Step-by-step explanation:

We can use a ratio to solve

4.2 k                  2 k

---------------- = ---------------

8.76                     x

Using cross products

4.2 * x = 2 * 8.76

4.2x =17.52

Divide by 4.2

x=4.17

zhuklara [117]3 years ago
5 0

Answer:

2kg cost £4.18

Step-by-step explanation:

4.2 kg of oranges cost £8.76

:. 1 kg of orange cost £8.76/4.2 = £2.09

2kg cost 2 × £2.09 = £4.18

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There will be 4 zeros
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Use the parabola tool to graph the quadratic function f(x)=−5x^2−2.
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Given that rectangle MNOP~ rectangle STUV~, what is the length of ___<br> TU
IrinaK [193]

A parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. The value of x or the length of TU is 22.5.

<h3>What is a rectangle?</h3>

That parallelogram in which adjacent sides are perpendicular to each other is called a rectangle. A rectangle is always a parallelogram and a quadrilateral but the reverse statement may or may not be true.

Since all the rectangles are similar, therefore, the corresponding sides of the rectangle will be in ratio. Therefore,

\dfrac{\text{Length of STUV}}{\text{Length of MNOP}} = \dfrac{9}{6}

Similarly, the breadth will be,

\dfrac{\text{Width of STUV}}{\text{Width of MNOP}} = \dfrac{\text{Length of STUV}}{\text{Length of MNOP}}\\\\\\\dfrac{\text{Width of STUV}}{\text{Width of MNOP}} = \dfrac{9}{6}\\\\\\\dfrac{x}{15}=\dfrac96\\\\\\x = \dfrac{9 \times 15}{6} = 22.5

Hence, the value of x or the length of TU is 22.5.

Learn more about Rectangle:

brainly.com/question/15019502

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5 0
2 years ago
Please help. Thank you!
katrin2010 [14]

Answer:

3a. ⇒ 2700 cm³

3b. ⇒ 72,900 cm³

3c. ⇒ 27

Step-by-step explanation:

3a.

∵ The model in a shape of square pyramid

∴ Its volume = base area × height

∵ Base shaped square with side length 15 cm

∴ Area of base = 15 × 15 = 225 cm²

∵ The model height = 12 cm

∴ She needs = 225 × 12 = 2,700 cm³ of plaster

3b.

∵ Each dimension in the actual stage = 3 times the model

∴ The side of the square base = 15 × 3 = 45 cm

∴ The height = 12 × 3 = 36 cm

∴ The area of the base = 45 × 45 = 2,025 cm²

∴ She needs = 2025 × 36 = 72,900 cm³ of plaster

3c.

∵ Each length in the actual stage is 3 times the model

∴ The volume of the actual stage = (3)³ the volume of the model

∴ The volume of the actual stage = 27 the volume of the model

<em>To check your answer:</em>

Volume actual ÷ Volume model = 72,900 ÷ 2700 = 27

3 0
3 years ago
Need help asap<br> will give brain
SCORPION-xisa [38]
Question 1 is F question 2 is D
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