Answer:
The equation is given by:
![D(t) = 80 + 9\sin{0.2618t}](https://tex.z-dn.net/?f=D%28t%29%20%3D%2080%20%2B%209%5Csin%7B0.2618t%7D)
Step-by-step explanation:
Sine function:
Has the following format:
![y = A\sin{bx}](https://tex.z-dn.net/?f=y%20%3D%20A%5Csin%7Bbx%7D)
In which A is the amplitude and
is the period.
Suppose you know the temperature is 80 degrees at midnight and the high and low temperature during the day are 89 and 71 degrees
This means that the amplitude of the sinusoidal variation function is 89 - 80 = 80 - 71 = 9. This means that ![A = 9](https://tex.z-dn.net/?f=A%20%3D%209)
During a 24-hour day, which means that the period is 24. So
![\frac{2\pi}{b} = 24](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Cpi%7D%7Bb%7D%20%3D%2024)
![24b = 2\pi](https://tex.z-dn.net/?f=24b%20%3D%202%5Cpi)
![b = \frac{2\pi}{24}](https://tex.z-dn.net/?f=b%20%3D%20%5Cfrac%7B2%5Cpi%7D%7B24%7D)
![b = 0.2618](https://tex.z-dn.net/?f=b%20%3D%200.2618)
So the variation is:
![V(t) = 9\sin{0.2618t}](https://tex.z-dn.net/?f=V%28t%29%20%3D%209%5Csin%7B0.2618t%7D)
Assuming t is the number of hours since midnight, find an equation for the temperature, D, in terms of t.
Initial temperature of 80, so:
![D(t) = 80 + V(t) = 80 + 9\sin{0.2618t}](https://tex.z-dn.net/?f=D%28t%29%20%3D%2080%20%2B%20V%28t%29%20%3D%2080%20%2B%209%5Csin%7B0.2618t%7D)
<span>False. A transformation changes the size, shape, or position of a figure and creates a new figure. So, no, not all transformations require a change in size.</span>
Answer:
x₁ = -4
x₂ = 3
Step-by-step explanation:
x²+ x + 12 = 0
x = {-1±√((1²)-(4*1*-12))} / (2*1)
x = {-1±√(1+48)} / 2
x = {-1±√49} / 2
x = {-1±7} / 2
x₁ = {-1-7} / 2 = -8/2 = -4
x₂ = {-1+7} / 2 = 6/2 = 3
Check:
x₁
-4² + (-4) - 12 = 0
16 - 4 - 12 = 0
x₂
3² + 3 - 12 = 0
9 + 3 - 12 = 0
Divide the two lengths:
(X'Z')/(XZ) = 5/4 = 1.25
The final answer is choice D) 1.25
This means that the larger figure is 25% bigger in size (comparing corresponding segments).
Answer:
Point A
Convert fraction into decimal =0.15