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Serhud [2]
3 years ago
7

PLEASE HELP I BEG YOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
ruslelena [56]3 years ago
7 0

Answer:

R1:   Given

R2:   Subtraction Property of Equality

R3:   Distribute Property

R4:   Addition Property of Equality

R5:   Division Property of Equality

Write a paragraph proof for the following conjecture: m∠1 + m∠2 = m∠4

Prove: m∠3 + m∠1 + m∠2 = 180°

Given: ∠1 + ∠2 = ∠ 4

∠4 + ∠3 must be 180° because they are supplementary

If ∠4 + ∠3 is 180, and ∠1 + ∠2 = ∠4, you can substitute ∠4 in the first equation for ∠1 + ∠2.

Hence, we arrive at the answer ∠1 + ∠2 + ∠3 = 180.

Plz mark brainliest:)

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Sums of a sequence: How many total gifts did my true love give to me during the entire 12 days of Christmas? Hint: Without any o
ale4655 [162]
<span> On the first day of Christmas,
my true love sent to me
A partridge in a pear tree. On the second day of Christmas,
my true love sent to me
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And a partridge in a pear tree. On the third day of Christmas,
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Three French hens,
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The song continues, adding 4 calling birds on the 4th day, 5 golden rings on the 5th, and so on up to the 12th day, when 12 drummers add to the cacophony of assorted birds, pipers and lords leaping all over the place.

Notice that on each day there is one partridge (so I will have 12 partridges by the 12th day), and each day from the second day onwards there are 2 doves (so I will have 22 doves), and from the 3rd there are 3 hens (total of 30 hens), and so on.

So, how many presents are there altogether?

Partridges: 1 × 12 = 12

Doves: 2 × 11 = 22

Hens 3 × 10 = 30

Calling birds: 4 × 9 = 36

Golden rings: 5 × 8 = 40

Geese: 6 × 7 = 42

Swans: 7 × 6 = 42

Maids: 8 × 5 = 40

Ladies: 9 × 4 = 36

Lords: 10 × 3 = 30

Pipers: 11 × 2 = 22

Drummers: 12 × 1 = 12

Total = 364

We observe that we have the same number of partridges as drummers (12 of each); doves and pipers (22 of each); hens and lords (30 of each) and so on. So the easiest way to count our presents is to add up to the middle of the list and then double the result: (12 + 22 + 30 + 36 + 40 + 42) × 2 = 364.


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Answer:

Huh?? I have no idea what you said.

Step-by-step explanation:

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Just #35 please piecewise functions
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Answer: No, the friend is correct. In any function, each input value can only lead to one output value. When you input 3 for the x-values, you would get two output values because 3 is included in both equations. To fix this, you need to have the 3 not included in one of the equations.

For example, you could say y=\left \{ {{2x-2, x\leq 3} \atop {-3, x > 3}} \right. or y=\left \{ {{2x-2, x < 3} \atop {-3, x\geq 3}} \right. because the input value of 3 would not be included twice.

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