Help find the value of x pls. No links! Y
1 answer:
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I did not get any zeros since the graph doesn’t cross the x axis, meaning that there are no rational zeros
However, here is the method u can use to find the zeros lol
You can use the quadratic formula in order to get the zeros
This is the equation therefore use these values
ax^2+bx+c=0
A=1
B= -5
C=12
The quadratic formula is -b±√(b^2-4ac))/2a (I left a picture just in case)
However, here is the method u can use to find the zeros lol
You can use the quadratic formula in order to get the zeros
This is the equation therefore use these values
ax^2+bx+c=0
A=1
B= -5
C=12
The quadratic formula is -b±√(b^2-4ac))/2a (I left a picture just in case)
To find the vertex of the parabola, we need to write it in a vertex form.
y=x² - 8x +12
1) complete the square
y=x² - 8x +12
y = x² -2*4x + 4² - 4² +12
y=(x-4)² -16 +12
2) calculate and write a vertex
y=(x-4)² -16 +12
y=(x-4)² - 4
(x-4) ----- x- coordinate of the vertex x=4
y=(x-4)² - 4 -------y- coordinate of the vertex y = - 4
Vertex is (4, -4).
Answer is (4, -4). No correct answer is given in choices.
y=x² - 8x +12
1) complete the square
y=x² - 8x +12
y = x² -2*4x + 4² - 4² +12
y=(x-4)² -16 +12
2) calculate and write a vertex
y=(x-4)² -16 +12
y=(x-4)² - 4
(x-4) ----- x- coordinate of the vertex x=4
y=(x-4)² - 4 -------y- coordinate of the vertex y = - 4
Vertex is (4, -4).
Answer is (4, -4). No correct answer is given in choices.