Simplify the product

1 answer:

7 0

How to get answer:

$((-2a^2)(b))(9a^5b^3-4ab^5)$

$=((-2a^2)(b))(9a^5b^3+-4ab^5)$

$=((-2a^2)(b))(9a^5b^3)+((-2a^2)(b))(-4ab^5)$

Answer: $=-18a^7b^4+8a^3b^6$

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