Rewriting the formula in standard form would be x^2-8x+14=0
The root

can be converted into the power

. Therefore we can rewrite the problem as

and then follow the exponent rules about a power to a power, multiplying 1/2 and 3/4 together.
Thus the problem becomes

, which then can be turned into
![\sqrt[8]{10} ^{3x}](https://tex.z-dn.net/?f=%20%5Csqrt%5B8%5D%7B10%7D%20%5E%7B3x%7D)
, making the last option our answer.
Answer:
b times l times w........
Answer:
n/6
Step-by-step explanation:
If angle bisector of angle DBC is BE. What is m angle EBC, then <DBE = <EBC
Since <ABC = <ABD+<DBC
n = 2<DBC+<DBC
n = 3<DBC
<DBC = n/3
Since <DBC = 2EBC
n/3 = 2<EBC
n/6 = <EBC
Hence <EBC = n/6
The solution is negative.