$78.90 cents
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If . he will use the wall of the garage as one side of the pen and will construct the rest of the rectangular pen from 28 yards of fencing. The maximum area that can be achieved for the dog pen is: 392 yards².
<h3>Maximum area </h3>
Let x represent the width of the fence
Let the two widths represent 2x
Let the length of one side represent 28-x
Let A represent Area
Hence,
A=x(28-x)
=-x²+28x
Using calculus or vertex = -b/2a,
x value = -28/-2
x = 14
2x = 28
So,
Maximum area= 14 ×28
Maximum area = 392 yards²
Therefore the maximum area is 392 yards².
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Answer:
6, 4, 5, 1, 3, 2, 7
Step-by-step explanation:
Sorry if I’m wrong
Answer:
The general equation following the pattern becomes is 7 + (n - 1)×2
Where, n = The figure number - 1
Step-by-step explanation:
The pattern in the question can be described as follows;
Figure 2 = (5 + 2) squares boxes = 7 squares boxes
Figure 3 = (5 + 2 + 2) squares boxes
Figure 4 = (5 + 2 + 2 + 2) squares boxes
Therefore, the number of squares boxes per figure, form an arithmetic progression (a + (n - 1)d) with the first term a = 7, the common difference d = 2, and the n = the nth term of the series, such that the general equation following the pattern becomes;
7 + (n - 1)×2.
