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Sergio039 [100]
3 years ago
8

Please answer as much as you can :)

Mathematics
1 answer:
zubka84 [21]3 years ago
3 0
Hope you have a great day today
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Help me please!!!??<br>​
Inessa [10]

Answer:

1/6

0.95833333333

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
7 . Sampling distribution of the difference between two means A statistician is interested in the effectiveness of a weight-loss
UkoKoshka [18]

Answer:

0.229

Step-by-step explanation:

Given that the difference between the two sample means follows anormal distribution with a mean of11.00 and standard deviation equal to1.4387

A statistician is interested in the effectiveness of a weight-loss supplement. She randomly selects two independent samples. Individuals in the first sample of size n1 = 24 take the weight-loss supplement. Individuals in the second sample of size n2 = 21 take a placebo. Individuals in both samples follow identical exercise and diet programs. At the end of the study, the statistician measures the weight loss (in percent) of each participant.

We find that mean difference actual = 13-2 = 11

Probability that difference >12 =P(Z>\frac{12-11}{1.3487} \\)

=P(Z>0.742)=.0.229

3 0
3 years ago
Please help me with this
kupik [55]

Answer:

–x² + 12x + 5

Step-by-step explanation:

x² + 3x

–2x² + 9x + 5

The sum of the above expression can be obtained as follow:

.... x² + 3x

+ –2x² + 9x + 5

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

–x² + 12x + 5

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

Thus, the sum of x² + 3x and –2x² + 9x + 5 is –x² + 12x + 5

3 0
3 years ago
Factor the trigonometric equation.<br> cos2x-cosx
prisoha [69]

Cos(2x) = cos^2(x) - sin^2(x) - cos(x)

but sin^2(x) = 1 - cos^2(x)

cos(2x) - cos(x) = cos^2(x) - (1 - cos^2(x) ) - cos(x)

cos(2x) - cos(x) = cos^2(x) - 1 + cos^2(x) - cos(x)

cos(2x) - cos(x) = 2cos^2(x) - 1 - cos(x)

cos(2x) - cos(x) = (2cos(x) + 1)(cos(x) - 1)

I think this is what you have asked for.

4 0
3 years ago
Expand 5(2x - 1) plsssss help some one
diamong [38]
10x-5

You multiply each term in the parentheses by 5
3 0
2 years ago
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