Here you have a system of 2 equations and 2 unknowns. An easy way to solve this type is to isolate one of the variables.
12a + 2b = 8
2b = 8 - 12a
b =

b = 4 - 6a
Now plug 4 - 6a into equation 1 to solve for a.
a + 5(4 - 6a) = 19
a + 20 - 30a = 19
-29a = -1
a = 1/29 (answer)
Now plug a into the equation for b
b= 4 - 6(1/29)
b= 110/29 (answer)
Pythagoras Theroem.
Leg₁²+leg₂²=hypotenuse²
Data:
Leg₁=48
hypotneuse=80
(48)²+ leg₂²=(80)²
2304+leg₂²=6400
leg₂²=6400-2304
leg₂²=4096
leg₂=√4096
leg₂=64
Answer: B. 64
Answer:
That looks confusing
Step-by-step explanation:
Answer:

Explanation:
In the first example the division results in a radical, not a polynomial.
The remaining examples are not counter-examples (they do result in a polynomial)
Answer:
3
Step-by-step explanation:
3