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Sunny_sXe [5.5K]
4 years ago
9

chase and sara went to the candy store. chase bought 5 pieces of fudge and 3 pieces of gum for 5.70. sara bought 2 pieces of fud

ge and 10 pieces of gum for 3.60. determne the cost of 1 piece of fudge and 1 piece of gum
Mathematics
1 answer:
Vilka [71]4 years ago
6 0
Let, the cost of 1 piece of fudge = x
Cost of a gum = y

System of equations: 5x + 3y = 5.70
2x + 10y = 3.60

Multiply 1st equation by 2, and second by 5, 
New equations: 10x + 6y = 11.40
10x + 50y = 18

Now, subtract 1st from 2nd, 
44y = 6.60
y = 6.60 / 44
y = 0.15

Substitute it in second equation, 
2x + 10(0.15) = 3.60
2x = 3.60 - 1.5
x = 2.10 / 2
x = 1.05

In short, Cost of a Fudge = $1.05 & Cost of a gum = $0.15

Hope this helps!
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Answer:

$20.15

Step-by-step explanation:

Given data

Original cost =  $9.57

Markup= 95%

Let us find the new cost of the basket

=95/100*9.57

=0.95*9.57

=$9.0915

Hence the cost of the basket is

= 9.57+9.0915

=18.66

Also, the sales tax is 8%

=8/100*18.66

=0.08*18.66

=1.4928

Therefore, the total amount to be paid is

=18.66+1.4928

=$20.15

8 0
3 years ago
Which hundredth is 8.275 beetween
bonufazy [111]

Answer:

the 7 is in the hundredths place

Step-by-step explanation:

hope this helps :)

8 0
3 years ago
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Find the slope of the line that contains the points (-5, 3) and (-1, -5).
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3 years ago
Rochelle earned $500 during the summer. She put 35% of this amount into savings. Which of the following fraction is equivalent t
vivado [14]

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Step-by-step explanation:

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6 0
3 years ago
Simplify. Can you explain it also?
Doss [256]

Answer:

The answer is

<h2>\frac{3c}{4e}</h2>

Step-by-step explanation:

<h3>\frac{9 {c}^{3}d {e}^{2}  }{12 {c}^{2} d {e}^{3} }</h3>

To solve the fraction reduce the fraction with d

That's we have

<h2>\frac{9 {c}^{3}  {e}^{2} }{12 {c}^{2} {e}^{3}  }</h2>

Next simplify the expression using the rules of indices to simplify the letters in the fraction

<u>For c </u>

Since they are dividing we subtract the exponents

We have

<h2>{c}^{3}  \div  {c}^{2}  =  {c}^{3 - 2}  = c^{1}  = c</h2>

<u>For </u><u>e</u>

<h2>e^{2}  \div  {e}^{3}  = e^{2 - 3}  =  {e}^{ - 1}  =  \frac{1}{e}</h2>

Substituting them into the expression we have

<h2>\frac{9c}{12e}</h2>

Reduce the fraction by 3

We have the final answer as

<h2>\frac{3c}{4e}</h2>

Hope this helps you

8 0
3 years ago
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