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irakobra [83]
3 years ago
11

To add or subtract fractions, what must you have?

Mathematics
2 answers:
emmasim [6.3K]3 years ago
8 0

Answer:

<em><u>Equal denominators/common denominators</u></em>

Step-by-step explanation:

You need to have equal denominators. If you do not, then you have to multiply the denominators against each other as well as multiplying the same number to the numerator. If a number is a factor of one of the numbers then multiply the number by its other factor so as to get the same number.

<em><u>Ex. 1</u></em>

<em><u>First one explained:</u></em>

2/3 + 4/5

1/3 * 5/5 = 5/15

2/5 * 3/3 = 6/15

5/15 + 6/15 = 11/15

<em><u></u></em>

<h2><em><u>Common denominator = 15</u></em></h2>

<em><u>Ex. 2</u></em>

<em><u>Second one explained:</u></em>

2/8 + 1/4

2/8 + 1/4*2/2 = 2/8 + 2/8

= 4/8

<h2><em><u>Common Denominator = 8</u></em></h2>

Hope this helped,

Kavitha Banarjee

antiseptic1488 [7]3 years ago
4 0

Answer:

You need a common denominator.

Step-by-step explanation:

3/4+2/3

9/12+8/12

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PLEASE HELP!! A classmate wrote the set notation for the values of the domain of a function {−5, −4, −3, −2, −1, 0} as {x | −5 ≤
vfiekz [6]
<h3>Answer: Choice B</h3>

The set notation includes all values from -5 to 0, but the domain only includes the integer values

eg: something like -1.2 is in the second set, but it is not in the set {-5,-4,-3,-2,-1}

==========================================================

Further explanation:

Let's go through the answer choices one by one

  • A. This is false because 0 does not come before -5, but instead -5 is listed first. The order -5,-4,-3,-2,-1,0 is correct meaning that -5 \le x \le 0 is the correct order as well.
  • B. This is true. A value like x = -1.2 is in the set \left\{x| -5 \le x \le 0\right\} since -1.2 is between -5 and 0; but -1.2 is not in the set {-5, -4, -3, -2, -1, 0}. So the distinction is that we're either considering integers only or all real numbers in this interval. To ensure that we only look at integers, the student would have to write \left\{x| x\in\mathbb{Z}, \ -5 \le x \le 0\right\}. The portion x \in \mathbb{Z} means "x is in the set of integers". The Z refers to the German word Zahlen, which translates to "numbers".
  • C. This is false. The student used the correct inequality signs to indicate x is -5 or larger and also 0 or smaller; basically x is between -5 and 0 inclusive of both endpoints. The "or equal to" portions indicate we are keeping the endpoints and not excluding them.
  • D. This is false. Writing -5 \ge x \ge 0 would not make any sense. This is because that compound inequality breaks down into -5 \ge x \ \text{ and } \ x \ge 0. Try to think of a number that is both smaller than -5 AND also larger than 0. It can't be done. No such number exists.
8 0
3 years ago
Find f(x) = 12/4x+2 find f(-1)
NeTakaya
X=-1
12/-4=-3
-3+2=-1
The correct answer is -1
3 0
3 years ago
Please explain how you get the answer to...<br> a+2a+7+4a-8
sammy [17]

Answer:

9+2a+7+4a-8

2a+16+4a-8

2a+8+4a

6a+8

Step-by-step explanation:

you can't really get an answer for this problem but you can simplify it

8 0
3 years ago
Am doing math and need help, don't understand it
kirill [66]

Answer:

ok

Step-by-step explanation:

i will ggfxhn. bjgxx

8 0
3 years ago
Read 2 more answers
The sum of two integers is 26. the sum of the squares of the two integers is 340. what is the product of the two numbers?
Phoenix [80]
Lets say that the two unknown integers are n and m.

We know the following things about n and m:

n+m=26
n^2+m^2=340

And, we want to find nm.

To solve this, we'll use the expansion of the squared of the sum of any two inegers; this is expressed as:

(n+m)^2=n^2+2nm+m^2

So, given what we know about the unknown integers, the previous can be written as:

(26)^2=340+2nm

We can easily solve for nm:

nm= \frac{(26)^2-340}{2}= \frac{676-340}{2}= \frac{336}{2}=168

The answer is 168.

Another approach to solve the problem is, from the two starting equations, compute the values of n and m, which are 12 and 14, and directly compute their product; however, the approach described is more elegant. 
5 0
3 years ago
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