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Norma-Jean [14]
3 years ago
12

How many 1/8-inch pieces of ribbon can be cut from a piece of ribbon that is 3/4 inch long? and I cant be a friction

Mathematics
1 answer:
Anarel [89]3 years ago
8 0

Answer:

100 inches

Step-by-step explanation:

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Transform the standard form equation into slope intercept form:15=10x-5y
arsen [322]

Answer:

10x - 5y = 15

-5y = -10x + 15

y = 2x - 3

Step-by-step explanation:

7 0
3 years ago
Ms. Moran has started an investment club at BSS. $8000 is invested, some at 10%
labwork [276]
The answer can be readily calculated using a single variable, x:

Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%

The problem is then stated as:

(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000

Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.
6 0
2 years ago
398.574986215 to the nearest ten-thousandth.
Julli [10]

Answer: 398.5750

Step-by-step explanation:

It is important to remember that the fourth digit after the decimal point is in the ten-thousandth place.

Then, given the  following number:

398.574986215

You can follow these steps in order ti round it to the nearest ten-thousandth:

1. You can identify that the digit in the ten-thousandth place is:

9

2. Identify the digit to the right of 9. This is:

8

3. Since:

 8>5

 You must round up. Increase the digit 9 by 1. (Notice that 9+1=10, then the digit to the left of  9 increases by 1 too). Then:

398.5750

3 0
3 years ago
Consider an object moving along a line with the given velocity v. Assume t is time measured in seconds and velocities have units
Yakvenalex [24]

Answer:

a) positive direction: t < 2s & t>6s   ; negative direction: 2s < t < 6s

b) 7 m

c) 71 m

Step-by-step explanation:

Given:

v(t) = 3t^2 -24t +36   [0 , 7]

Find:

a) The value of time when particle is moving in positive direction:

The change in direction of the particle can be determined by v(t) > 0

Hence,

                                    0 < 3t^2 -24t +36

                                    0 < t^2 - 8t + 12

                                    0 < (t - 2)*(t - 6)

                                    t < 2s  , t  > 6s  

The particle travels in positive direction in the interval t < 2s and t > 6s , While it travels in negative direction when 2s < t < 6s.

b) The displacement ds over the given interval [ 0 , 7 ]

                                  ds = integral (v(t)).dt

                                  ds = t^3 -12t^2 +36t

                                  ds = 7^3 -12*7^2 +36*7

                                  ds = 7 m

c) Total distance traveled in the interval:

                                 Total distance= ds(0-2) + ds(2-6) + ds(6-7)

                                 D = 2*(2^3 -12*2^2 +36*2) - 2*(6^3 -12*6^2 +36*6) + 7

                                 D = 2*32 - 2*0 + 7

                                 D = 71 m          

     

6 0
3 years ago
Please help figure this out
expeople1 [14]

Answer:

1st. Common Difference of 3

2nd. Not Arithmetic

3rd. Not Arithmetic

Step-by-step explanation:

The 1st one, you can add to get the next number, but the other ones you have to multiply.

4 0
2 years ago
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