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VladimirAG [237]
3 years ago
15

Joyce paid $50 for an item at the store that was 45 percent of the original price. What was the original price?

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer:

$69 is the original price

Step-by-step explanation:

Look aboveee

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I put a picture
Ksivusya [100]

Answer:

Yes, an arrow can be drawn from 10.3 so the relation is a function.

Step-by-step explanation:

Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.

The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.

In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.

However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.

3 0
3 years ago
How many centimeters are there in 75 meters?
kumpel [21]

Answer:

7500. There are 100 centimeters in a meter therefore 75 meters have 7500 centimeters.

3 0
3 years ago
Read 2 more answers
the perez family has a rectangle fish tank. How much water will the tank hold if its length is 3 feet, its width is 2 feet, and
myrzilka [38]

V = 3 x 2 x 3 = 18

answer

B) 18 cubic feet

7 0
3 years ago
Which is the value of this expression when a=5 and k=-2
Zinaida [17]

Answer:

Option C is correct.

Step-by-step explanation:

We are given the expression:

(\frac{3^2a^{-2}}{3a^{-1}})^k

The value of a =5 and k = -2

Putting the values and solving

=(\frac{3^2*5^{-2}}{3*5^{-1}})^-2\\=(\frac{3^{2-1}}{5^{-1+2}})^-2\\=(\frac{3^{1}}{5^{1}})^-2\\\\=(\frac{3}{5})^-2\\if \,\,a^{-1} \,\,then\,\, 1/a\\=\frac{(3)^{-2}}{(5)^{-2}}\\ Can\,\,be\,\,written\,\,as\\\\=\frac{(5)^{2}}{(3)^{2}} \\=\frac{25}{9}

Option C is correct.

3 0
3 years ago
A random sample has been selected from a population. The point estimate = 78.65 and margin of error E = 8.24 for a 90% confidenc
fiasKO [112]

Answer:

90% confidence interval: (70.41,86.89)

Step-by-step explanation:

We are given the following in the question:

Point estimate = 78.65

Margin of error, E = 8.24

Confidence level = 90%

Significance level = 10%

Formula:

\text{Point estimate} \pm \text{Margin of error}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.10} = \pm 1.64

78.65 \pm 8.24 = (70.41,86.89)

(70.41,86.89) is the required 90% confidence interval.

5 0
3 years ago
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