Answer:
They are all correct. Well done.
Cone Volume = (PI * radius^2 * height) / 3
3 = (PI * radius^2* x) / 3
radius^2 = 9 / (PI * x)
radius = square root (9 / (PI * x))
Answer:
(a)


(b)
B. The sample is too small to make judgments about skewness or symmetry.
Step-by-step explanation:
Given:


Solving (a):
First, calculate the difference between the recorded TBBMC for both operators:

The last row which represents the difference between 1 and 2 is calculated using absolute values. So, no negative entry is recorded.
The mean is then calculated as:




Next, calculate the standard deviation (s).
This is calculated using:

So, we have



Solving (b):
Of the given options (A - E), option B is correct because the sample is actually too small
Answer:
You can use something called Desmos... I hope this helped
Step-by-step explanation: