The critical points of the function graphed are given as follows:
<h3>What are the critical points of a function?</h3>
The critical points of a function are the values of x for which:
In a graph, they are turning points, and are classified as follows:
- Local maximum, if the functions changes from increasing to decreasing.
- Local minimum, if the functions changes from decreasing to increasing.
Looking at the graph, the turning points are approximately:
More can be learned about critical points at brainly.com/question/2256078
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Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula
x+y=8
xy=28
x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0
if you have
ax^2+bx+c=0 then x=
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28
x=
x=
x=
x=
x=
there are no real numbers that satisfy this
Answer:
c=0
Step-by-step explanation:
ATQ a.b=|a||b|sin(45)
1+c=sqrt(1+c^2)*sqrt(2)*1/sqrt(2)
1+c=sqrt(1+c^2)
(1+c)^2=(1+c^2)
2c=0, c=0
6 over negative 10, because you just multiply the numerator and denominator by 2
Answer:
9
Step-by-step explanation:
Since 12 divided by 4 is 3, that is the constant. So 3 times 3 is 9
