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3 years ago

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What is the equivalent ratio of 4:2 = 20:__

1 answer:

Alina [70]3 years ago

5 0

Answer: 20:10

Step-by-step explanation:

you can set up a ratio for this one

4/2 = 20/x

4x = 40

x = 10

or you can 20/4 = 5

5 x 2 = 10

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(−5k<br> 3<br> −6k+1)+(−6k<br> 2<br> +5k)

Fittoniya [83]

Remove unnecessary parenthesis.

-5k 3 - 6k +1 - 6k 2 + 5k (simplify each term) -15k - 6k + 1 - 12k +5k = -28k +1

Answer: 28k + 1

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3 years ago

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HELP!!! STATS!!!

Vadim26 [7]

Answer:

The 99% confidence interval is $165.776 < \mu < 180.224$

Step-by-step explanation:

From the question we are told that

The sample size is n = 100

The sample mean is $\= x = 173 \ days$

The population standard deviation is $\sigma = 28 \ days$

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

$E = 2.58 * \frac{28 }{\sqrt{100} }$

=> $E = 7.224$

Generally 95% confidence interval is mathematically represented as

$\= x -E < \mu < \=x +E$

=> $173 -7.224 < \mu < 173 + 7.224$

=> $165.776 < \mu < 180.224$

4 0

3 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

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2 years ago

The _____________________________________ Postulate says that If two angles of one triangle are congruent to two angles of anoth

Crank

Answer: Angle sum

Step-by-step explanation:

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2 years ago

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SCORPION-xisa [38]

Answer:

$6\pi u^3 = 18.8u^3$

Step-by-step explanation:

the information we have is:

the radius of the circle in the base: $r=3u$ (u for units)

and the height of the cone: $h=2u$

to find the volume we need the formula for the volume of a cone:

$V=\frac{\pi r^2h}{3}$

where r is the radius and h is the height.

Substituting the known values to find the volume:

$V=\frac{\pi (3u)^2(2u)}{3} \\\\V=\frac{\pi (9u^2)(2u)}{3}\\ \\V=\frac{18\pi u^3}{3}\\ \\V=6\pi u^3$

the volume in terms of $\pi$ is $6\pi u^3$

and if we substitute the value of pi: $\pi=3.14$ we get:

$V=6(3.14)u^3\\V=18.8u^3$

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3 years ago

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