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Sergio [31]
3 years ago
11

The given dot plot represents the average daily temperatures, in degrees Fahrenheit, recorded in a town during the first 15 days

of September. If the dot plot is converted to a box plot, the first quartile would be drawn at , and the third quartile would be drawn at .
Mathematics
1 answer:
ElenaW [278]3 years ago
4 0

Answer:

Q1 = 61

Q3 = 63

Step-by-step explanation:

From the plot attached :

Data obtained is :

Temperature frequency

59 0

60 2

61 3

62 3

63 4

64 2

65 1

Frequency Total 15

Data in raw format :

60,60,61,61,61,62,62,62,63,63,63,63,64,64,65

The first quartile :

Q1 = 1/4(n+1)th term

n = 15

Q1 = 1/4(15+1)th term

Q1 = 1/4 * 16th

Q1 = 4th term

Q1 = 61

Third quartile (Q3):

Q3 = 3/4(n+1)th term

n = 15

Q3 = 3/4(15+1)th term

Q3 = 3/4 * 16th

Q3 = (48/4)th term

Q3 = 12th term

Q3 = 63

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What is the sum of -14<br> and -15?
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Dragon drop each expression two correctly classify it as having a positive or negative product
ioda

Step-by-step explanation:

We multiply it to find the product

positive times positive = positive

positive times negative = negative

negative times positive = negative

negative times negative = positive

(-\frac{1}{3})(-\frac{1}{3})= \frac{1}{9}

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(-\frac{1}{3})(\frac{1}{3})= -\frac{1}{9}

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7 0
3 years ago
The probability that a household owns a pet is 0. 55. Suppose there are 5 houses on a block. Assuming each household is independ
Alexandra [31]

If the probability that a household owns a pet is 0.55 then the probability that all households will have pets is equal to 0.0503.

Given that the probability that a household owns a pet is 0.55 and there are 5 houses on a block.

We are required to calculate the probability that all the five households will have pets.

Probability is basicallly the chance of happening an event among all the events possible. It cannot be negative.

Binomial probability distribution is basically the probability calculations but in different combinations.

In this we have to calculate the probability that all the houses will have the pets then the probability that all five households will have pets is equal to 5C_{5}(0.55)^{5} (1-0.55)^{0}

=1(0.0503)(0.45)^{0}

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Hence the probability that all the five households will have pets is equal to 0.0503.

Learn more about probability at brainly.com/question/24756209

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