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3 years ago

The expression 2 log x - (3 log y + log z) is equivalent to

Mathematics

1 answer:

dmitriy555 [2]3 years ago

6 0

Answer:

$2 log(x )- (3 log(y) + log(z) ) \\ \equiv log( {x}^{2} ) - log( {y}^{3} ) - log(z) \\ \equiv log( \frac{x {}^{2} }{ {y}^{3} + z} )$

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Help me with this please

alina1380 [7]

If you assign variables to the problem, it can make things a lot simpler. Lets say chairs are x and tables are y. Therefore you have:
2x+6y=40
5x+3y=25
Now you can isolate the variable of one equation and put it into another (it doesn't matter which. I'm going to manipulate the top equation to plug into the bottom one).
2x=40-6y
x=20-3y
Now I plug into bottom equatioin:
5(20-3y) + 3y=25
100-15y+3y=25
100-12y=25
-12y=-75
y=$6.25
Now you can plug in y in either equation to get x.
2x+6(6.25)=40
37.5+2x=40
2x=2.5
x=1.25
So it costs $6.25 for each table and $1.25 for each chair. If you think about it, it would make sense for the table to cost more for the chair.

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4 years ago

A test subject is randomly selected for a pregnancy test. What is the probability of getting a subject who is not pregnant, give

Scilla [17]

First we need to choose from "Posivite Test" column:
$\frac{12}{12+78} = \frac{12}{90} = 0,1333(3)$

3 0

4 years ago

Read 2 more answers

I’m not to sure what one it is

DENIUS [597]

(6,5) is the only pair that you will find in the table.

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3 years ago

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Evaluate |-a 2 ), given a = 5, b = -3, and c = -2. 25 -25 -10 10

Temka [501]

Answer:

1-a2

1-5x2

-4x2= -8

Step-by-step explanation:

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3 years ago

Use the Distance Formula and the Pythagorean Theorem to find the distance between each pair of points. M (10, −4) and N (2, −7)

xenn [34]

Answer:

$d=\sqrt{73}\approx8.54$

Step-by-step explanation:

So we have the two points (10,-4) and (2,-7).

And we want to find the distance between them using the Distance Formula and the Pythagorean Theorem. Let's do each one individually.

1) Distance Formula.

The distance formula is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Let's let (10,-4) be (x₁, y₁) and let's let (2,-7) be (x₂, y₂). So:

$d=\sqrt{((2)-(10))+((-7)-(-4))^2$

Simplify:

$d=\sqrt{(2-10)^2+(-7+4)^2$

Subtract:

$d=\sqrt{(-8)^2+(-3)^2$

Square:

$d=\sqrt{64+9}$

Add:

$d=\sqrt{73}$

Approximate:

$d\approx8.54$

So, the distance between (10,-4) and (2,-7) is approximately 8.54 units.

2) Pythagorean Theorem

Please refer to the graph.

So, we want to find the distance. This will be the length of the red line, or the hypotenuse.

First, let's find the length of the two legs.

The longer leg will be the difference between the two x-coordinates. So, the length of the longer leg is:

$(10-2)=8$

Note: It doesn't matter if we do 2-10, which gives -8, since we are going to square anyways. Also, distance is always positive, so 8 would be our answer.

And the shorter leg is the difference between the two y-coordinates. Namely:

$(-7-(-4))=-3=3$