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drek231 [11]
3 years ago
7

What is the midpoint of EC ?

Mathematics
1 answer:
sladkih [1.3K]3 years ago
4 0

<u>Given</u>:

Given that the graph OACE.

The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)

We need to determine the midpoint of EC.

<u>Midpoint of EC:</u>

The midpoint of EC can be determined using the formula,

Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})

Simplifying, we get;

Midpoint=(\frac{2(t+p)}{2},\frac{2r}{2})

Dividing, we get;

Midpoint=(t+p,r)

Thus, the midpoint of EC is (t + p, r)

Hence, Option A is the correct answer.

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What is the value of the expression: 2 - (3x + 5y) if x = -3 and y = 4?
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<h3>Hello there today we will solve your problem</h3>

here is our equation,

2-(3x+5y),

Now we will plug in our numbers

__________________

  1. {\boxed{x=-3}}
  2. {\boxed{y=4}

__________________

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