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drek231 [11]
3 years ago
7

What is the midpoint of EC ?

Mathematics
1 answer:
sladkih [1.3K]3 years ago
4 0

<u>Given</u>:

Given that the graph OACE.

The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)

We need to determine the midpoint of EC.

<u>Midpoint of EC:</u>

The midpoint of EC can be determined using the formula,

Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})

Simplifying, we get;

Midpoint=(\frac{2(t+p)}{2},\frac{2r}{2})

Dividing, we get;

Midpoint=(t+p,r)

Thus, the midpoint of EC is (t + p, r)

Hence, Option A is the correct answer.

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<u>Step-by-step explanation:</u>

Need to find the slope (m):

  \dfrac{y_2-y_1}{x_2-x_1}

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= \dfrac{0}{-4}

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Now input ONE of the points (1, 4) and the slope (m = 0) into the Point-Slope formula:

y - y₁ = m(x - x₁)

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********************************************************************

4. Answer: \bold{y = \dfrac{2}{3}x + 3}

<u>Step-by-step explanation:</u>

 y - y_1 = m(x - x_1)

 y - 1 = \dfrac{2}{3}(x - (-3))

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 y - 1 = \dfrac{2}{3}x + 2

 y = \dfrac{2}{3}x + 3


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3 years ago
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