Answer:
51.96 mm² approximately
Step-by-step explanation:
the first thing you should know is that the area of a rectangle is base*height sin of (
the included angle i.e
Arectangle= bh sin90° since all angles of a rectangle are equal then the included angle is 90°
<em>Arectangle= bh sin90° since sin90 is 1 we simply use the equation bh because multiplying bh by one is bh. bearing this in mind , the area of the parallelogram can be calculated as:</em>
Aparallelogram= bh sin of sin of the included angle
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866
Aparallelogram= bh sin of sin of the included angle Aparallelogram=6mm*10mm sin 60°Aparallelogram=60mm² * 0.866Aparallelogram=51.96 mm² approximately
Answer:
109.5; B
Step-by-step explanation:
From your identity,
CosA = adjacent/ hypothenus
A represent an arbitrary angle between the sides in question.
In the question above, A=64
Hypothenus is the longest side and adjacent is the side just below the angle .
In the above case,
Hypothenus= X
adjacent =48
This means;
Cos64 = 48 /X
X = 48 / cos64; [ from cross multiplication and diving through by cos64]
X = 48 /0.4383 [ cos64 in radian = 0.4383]
= 109.51
= 109.5 to the nearest tenth.
Note( do your calculation of angle in radian or else, you won't get the answer)
Answer:
its 10 in
Step-by-step explanation:
∵∴∵∴∵∴∵∴∵
⊕ΘΞΠΤ⊕
∵∴∵∴∵∴∵∴∵
Answer:
c
Step-by-step explanation:
because it's her extraneous uncontrolled variable
(f+g)(x)=5x-6+x^2-4x-8
A.(f+g)(x)=x^2+x-14 is correct:)
